我有两列的DataFrame,类型为ID
的Int
和类型为Vec
(Vector
)的org.apache.spark.mllib.linalg.Vector
。
DataFrame如下所示:
ID,Vec
1,[0,0,5]
1,[4,0,1]
1,[1,2,1]
2,[7,5,0]
2,[3,3,4]
3,[0,8,1]
3,[0,0,1]
3,[7,7,7]
....
我想做一个
groupBy($"ID")
,然后通过对向量求和来对每个组内的行应用聚合。上面的示例的期望输出将是:
ID,SumOfVectors
1,[5,2,7]
2,[10,8,4]
3,[7,15,9]
...
可用的汇总功能将无法使用,例如
df.groupBy($"ID").agg(sum($"Vec")
将导致ClassCastException。如何实现一个自定义聚合函数,该函数使我可以对向量或数组求和或执行任何其他自定义操作?
最佳答案
Spark> = 3.0
您可以将Summarizer
与sum
一起使用
import org.apache.spark.ml.stat.Summarizer
df
.groupBy($"id")
.agg(Summarizer.sum($"vec").alias("vec"))
Spark
就个人而言,我不会为UDAF所困扰。除了冗长而且不完全是快速的(Spark UDAF with ArrayType as bufferSchema performance issues),我将只使用
reduceByKey
/foldByKey
:import org.apache.spark.sql.Row
import breeze.linalg.{DenseVector => BDV}
import org.apache.spark.ml.linalg.{Vector, Vectors}
def dv(values: Double*): Vector = Vectors.dense(values.toArray)
val df = spark.createDataFrame(Seq(
(1, dv(0,0,5)), (1, dv(4,0,1)), (1, dv(1,2,1)),
(2, dv(7,5,0)), (2, dv(3,3,4)),
(3, dv(0,8,1)), (3, dv(0,0,1)), (3, dv(7,7,7)))
).toDF("id", "vec")
val aggregated = df
.rdd
.map{ case Row(k: Int, v: Vector) => (k, BDV(v.toDense.values)) }
.foldByKey(BDV.zeros[Double](3))(_ += _)
.mapValues(v => Vectors.dense(v.toArray))
.toDF("id", "vec")
aggregated.show
// +---+--------------+
// | id| vec|
// +---+--------------+
// | 1| [5.0,2.0,7.0]|
// | 2|[10.0,8.0,4.0]|
// | 3|[7.0,15.0,9.0]|
// +---+--------------+
只是为了比较,一个“简单的” UDAF。所需进口:
import org.apache.spark.sql.expressions.{MutableAggregationBuffer,
UserDefinedAggregateFunction}
import org.apache.spark.ml.linalg.{Vector, Vectors, SQLDataTypes}
import org.apache.spark.sql.types.{StructType, ArrayType, DoubleType}
import org.apache.spark.sql.Row
import scala.collection.mutable.WrappedArray
类定义:
class VectorSum (n: Int) extends UserDefinedAggregateFunction {
def inputSchema = new StructType().add("v", SQLDataTypes.VectorType)
def bufferSchema = new StructType().add("buff", ArrayType(DoubleType))
def dataType = SQLDataTypes.VectorType
def deterministic = true
def initialize(buffer: MutableAggregationBuffer) = {
buffer.update(0, Array.fill(n)(0.0))
}
def update(buffer: MutableAggregationBuffer, input: Row) = {
if (!input.isNullAt(0)) {
val buff = buffer.getAs[WrappedArray[Double]](0)
val v = input.getAs[Vector](0).toSparse
for (i <- v.indices) {
buff(i) += v(i)
}
buffer.update(0, buff)
}
}
def merge(buffer1: MutableAggregationBuffer, buffer2: Row) = {
val buff1 = buffer1.getAs[WrappedArray[Double]](0)
val buff2 = buffer2.getAs[WrappedArray[Double]](0)
for ((x, i) <- buff2.zipWithIndex) {
buff1(i) += x
}
buffer1.update(0, buff1)
}
def evaluate(buffer: Row) = Vectors.dense(
buffer.getAs[Seq[Double]](0).toArray)
}
以及示例用法:
df.groupBy($"id").agg(new VectorSum(3)($"vec") alias "vec").show
// +---+--------------+
// | id| vec|
// +---+--------------+
// | 1| [5.0,2.0,7.0]|
// | 2|[10.0,8.0,4.0]|
// | 3|[7.0,15.0,9.0]|
// +---+--------------+
另请参阅:How to find mean of grouped Vector columns in Spark SQL?。
关于scala - 如何定义自定义聚合函数以对Vector的列求和?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/44561255/