我想创建一个动态创建表的方法,只是将表名作为变量传递。
我已经定义了xml映射器
<mapper namespace="com.mappers.TableCreatorMapper">
<cache />
<insert id="createNewTableIfNotExists" parameterType="String" >
CREATE TABLE IF NOT EXISTS #{tableName}
(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
)
ENGINE=InnoDB
</insert>
</mapper>
我的Java接口映射器很简单:
public interface TableCreatorMapper {
public void createNewTableIfNotExists(String tableName);
}
但当我调用接口时
tableCreatorMapper.createNewTableIfNotExists("test");
我得到以下异常:
org.springframework.jdbc.BadSqlGrammarException:
### Error updating database. Cause: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''test'
(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
' at line 1
### The error may involve com.mappers.TableCreatorMapper.createNewTableIfNotExists-Inline
### The error occurred while setting parameters
### SQL: CREATE TABLE IF NOT EXISTS ? ( `ID` varchar(20) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=InnoDB
### Cause: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''test'
(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
' at line 1
; bad SQL grammar []; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''test'
(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
' at line 1
at org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator.doTranslate(SQLErrorCodeSQLExceptionTranslator.java:231)
at org.sp
如果我改为在查询中添加表名的``
CREATE TABLE IF NOT EXISTS `#{tableName}`(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
)
ENGINE=InnoDB
我明白了
### The error occurred while setting parameters
### SQL: CREATE TABLE IF NOT EXISTS `?`( `ID` varchar(20) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=InnoDB
### Cause: java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
; SQL []; Parameter index out of range (1 > number of parameters, which is 0).; nested exception is java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
知道为什么吗?
最佳答案
尝试
CREATE TABLE IF NOT EXISTS ${_parameter}
(
`ID` varchar(20) NOT NULL,
PRIMARY KEY (`ID`)
)
ENGINE=InnoDB
#{name}用于preparedstatement中的参数(请参见Parameters中的字符串替换)。