对于我的公司,我必须开发一个可以使用GPS坐标绘制路径的功能。确实,我的公司使用GPS来跟踪多次比赛中的跑步者。
因此,我尝试了多种方法来绘制折线,我的最新版本是:
_public.drawPolyline = function(pool, id, points, color, opacity, weight) {
try {
var l = points.length;
var latlngs = [];
var j=1;
for (var i = 0; i < l; i++) {
latlngs[i] = new ol.geom.Point(ol.proj.transform([points[i].longitude, points[i].latitude], 'EPSG:4326', 'EPSG:3857'));
};
var style = new ol.style.Style({
stroke: new ol.style.Stroke({
color: color,
width: weight,
opacity: opacity,
radius: 6
})
});
//Check if pool exists, else create it
if (!_private._polyline.containsKey(pool)) {
_private._polyline.put(pool, new jQuery.Hashtable())
}
var currentPool = _private._polyline.get(pool);
//Check if line exists, if yes, update path
if (currentPool.containsKey(id)) {
var vectorLayer = currentPool.get(id).layer;
vectorLayer.setVisible(true);
} else {
var linefeature = new ol.source.Vector('Path', {styleMap: style});
var comp = new ol.geom.LineString(latlngs);
var featurecomp = new ol.Feature({
name: "Comp",
geometry: comp
});
var vector = new ol.layer.Vector({
title: pool,
visible: true,
source: linefeature
});
linefeature.addFeatures(featurecomp);
currentPool.put(id, linefeature);
currentPool.put(id, { "type": "Path", "url": id, "layer": vector });
var vectorLayer = currentPool.get(id).layer;
vectorLayer.setVisible(true);
}
} catch (e) {
console.log(e.message);
}
}
因此,我想绘制一个带有不同参数的函数的折线:
-池:存储我的折线的哈希表
-ID:不重要
-点:包含一个对象数组(
{"location":[{"id":1854703,"latitude":42.831,"longitude":0.30087,"altitude":0,"hpl":0,"vpl":0,"speed":4,"direction":258,"date":"2012-08-25 03:43:23","device_id":786,"datereceived":"2012-08-25 03:43:23"}
)。根据我的测试服务器,我的日志中没有错误,但是,我仍然没有绘制折线。
如果有人可以帮助我,那就太好了。
问候,Brz。
最佳答案
您只需要如下创建LineString点
points.push(ol.proj.transform([xx,yy],'EPSG:4326', 'EPSG:3857'));
演示链接https://plnkr.co/edit/WqWoFzjQdPDRkAjeXOGn?p=preview
编辑
var vectorSource = new ol.source.Vector({});
var vectorSourcePoint = new ol.source.Vector({});
var style = new ol.style.Style({
image: new ol.style.Circle({
radius: 4,
fill: new ol.style.Fill({
color: color
}),
stroke: new ol.style.Stroke({
color: color,
width: weight,
opacity: opacity
})
})
});
var l = points.length;
var latlngs = [];
for (var i = 0; i < l; i++) {
latlngs.push(ol.proj.transform([points[i].longitude, points[i].latitude],'EPSG:4326', 'EPSG:3857'));
//below 3 lines of code creates point geometry. I think you don't need this
var point = new ol.geom.Point([points[i].longitude, points[i].latitude]).transform('EPSG:4326', 'EPSG:3857');
var fea = new ol.Feature({geometry:point});
vectorSourcePoint.addFeature(fea);
};
//below lines of code creates polyline. You are missing these lines.
var thing = new ol.geom.MultiLineString([points]);
var featurething = new ol.Feature({
name: "Thing",
geometry: thing
});
vectorSource.addFeature( featurething );