(我有以下代码,它们想要实现服务器端应用程序并向客户端发送响应:
class client(Thread):
def __init__(self, socket, address):
Thread.__init__(self)
self.sock = socket
self.addr = address
self.start()
def run(self):
request=''
while 1:
data=self.sock.recv(1024).decode() #the program hangs here with large message
if not data:
break
request+=data
print(request, self.addr[1], self.addr[0]))
message = "test"
self.sock.send(message.encode())
def init_server():
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.bind((host, int(port)))
serversocket.listen(5)
while 1:
clients, address = serversocket.accept()
client(clients, address)
return
现在,我编写一个简单的客户端:
client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(('localhost', 8000))
client_socket.send(message)
request = ''
while 1:
data = client_socket.recv(2048).decode()
if not data:
break
request += data
print(request)
client_socket.close()
现在的问题是服务器挂在具有大消息的recv中。怎么解决?
最佳答案
您的客户端套接字和服务器套接字是不同的套接字。
您可以使用serversocket
对象获取服务器信息,方法与尝试self.sock
相同。
我建议将serversocket
作为第三个参数解析到您的client
类中,然后像这样在类中使用它
class client(Thread):
def __init__(self, socket, address, server):
Thread.__init__(self)
self.sock = socket
self.addr = address
self.server = server
self.start()
def run(self):
request=''
while 1:
data=self.sock.recv(1024).decode()
if not data:
break
request+=data
print(request, self.server.getsockname()[1], self.server.getsockname()[0]))
def init_server():
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.bind((host, int(port)))
serversocket.listen(5)
while 1:
clients, address = serversocket.accept()
client(clients, address, serversocket)
return
那应该输出服务器信息
如果需要客户端信息,则将其作为“元组”解析为“地址”,则可以看到用于进行通信的远程IP和套接字端口(不是开放端口)