clang - 使用LLVM LibFuzzer时'fsantize-coverage = edge'中的无效值'edge'

http://llvm.org/docs/LibFuzzer.html
我现在正在使用libfuzzer做一些工作，但是当我使用官方玩具示例时。当我运行此命令时：

clang++ -fsanitize=address -fsanitize-coverage=edge test-fuzzer.cc Fuzzer*.o

发生错误

clang: error: invalid value 'edge' in 'fsanitize-coverage=edge'

似乎clang支持此参数，但我想知道如何查看支持的值...
我用unbuntu14.04通过apt-get安装了llvm 3.6

最佳答案

fsanitize-coverage=标志的语法已更改，如2015年5月的this commit message中所述。此位与您特别相关：

Original semantics of -fsanitize-coverage flag is preserved:
  * -fsanitize-coverage=0 disables the coverage
  * -fsanitize-coverage=1 is a synonym for -fsanitize-coverage=func
  * -fsanitize-coverage=2 is a synonym for -fsanitize-coverage=bb
  * -fsanitize-coverage=3 is a synonym for -fsanitize-coverage=edge
  * -fsanitize-coverage=4 is a synonym for -fsanitize-coverage=edge,indirect-calls

因此，您可以尝试-fsanitize-coverage=3。

关于clang - 使用LLVM LibFuzzer时'fsantize-coverage = edge'中的无效值'edge'，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/38902683/