我在Zeppelin 0.7笔记本中使用Spark 2和Scala 2.11。我有一个可以这样打印的数据框：
dfLemma.select("text", "lemma").show(20,false)
输出看起来像：
+---------------------------------------------------------------------------------------------------------------------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|text |lemma |
+---------------------------------------------------------------------------------------------------------------------------+-----------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|RT @Dope_Promo: When you and your crew beat your high scores on FUGLY FROG 😍🔥 https://time.com/Sxp3Onz1w8 |[rt, @dope_promo, :, when, you, and, you, crew, beat, you, high, score, on, FUGLY, FROG, https://time.com/sxp3onz1w8] |
|RT @axolROSE: Did yall just call Kermit the frog a lizard? https://time.com/wDAEAEr1Ay |[rt, @axolrose, :, do, yall, just, call, Kermit, the, frog, a, lizard, ?, https://time.com/wdaeaer1ay] |
我试图通过以下方式使齐柏林飞艇的输出更好：
val printcols= dfLemma.select("text", "lemma")
println("%table " + printcols)
给出以下输出：
printcols: org.apache.spark.sql.DataFrame = [text: string, lemma: array<string>]
并以新的空白齐柏林飞艇为标题
[text: string, lemma: array]
有没有一种方法可以使数据框显示为格式正确的表格？
TIA！
最佳答案
在Zeppelin中，您可以使用z.show(df)显示漂亮的表格。这是一个例子：
val df = Seq(
(1,1,1), (2,2,2), (3,3,3)
).toDF("first_column", "second_column", "third_column")
z.show(df)