我正在尝试在数据库中检查用户名,当我这样做时它可以用于第一个用户名,但在它不能正常工作后,我想我明白为什么,但是我无法解决其他问题。
这是我的代码:
import sqlite3
conn = sqlite3.connect('tutorial.db')
c = conn.cursor()
def username():
global limit
global usernameinput
usernameinput = input("What would you like your username to be?")
limit = 0
select_all_tasks(conn)
def create_table():
c.execute('CREATE TABLE IF NOT EXISTS stuffToPlot(username TEXT,
password TEXT)')
conn.close
def select_all_tasks(conn):
global limit
global passwordinput
global rows
c.execute("SELECT * FROM stuffToPlot")
rows = c.fetchall()
for row in rows:
print(row)
if usernameinput in row:
print("Username Taken")
username()
else:
if limit < 1:
passwordinput = input("What would you like your password to
be?")
limit = limit + 1
def data_entry():
global passwordinput
global row
c.execute("INSERT INTO stuffToPlot VALUES(?, ?);",(usernameinput,
passwordinput))
conn.commit()
c.close()
conn.close()
create_table()
username()
select_all_tasks(conn)
data_entry()
没有错误,只是没有注册用户名已经在数据库中。
最佳答案
您需要缩进if语句和以下所有行以使其起作用,否则仅测试最后一行。
for row in rows:
print(row)
if usernameinput in row:
print("Username Taken")
您也可以使其更简单:
# select only the field "username" from the table
c.execute("SELECT username FROM stuffToPlot")
# build a set with all names, from the results given as [('name1',), ('name2',), ('name3',)]
names = {name[0] for name in c.fetchall()}
if usernameinput in names:
print("Username Taken")
username()
else:
if limit < 1:
关于python - 如何检查SQLite数据库中的用户名? python ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47005179/