问题描述
如果您下载目录,Google Drive 网络界面允许您下载单个 .zip 文件.但是,我发现无法使用 API 做到这一点.是否可以使用 API 在驱动器上创建多文件 zip?
The Google Drive web interface allows you to download a single .zip file if you download a directory. However, I find no way to do that with the API. Is it possible to create a multi file zip on drive with the API?
更新:Tanakie 的代码有效!这很棒!但是,我只能在我的个人帐户中使用它.我有两个 G-Suite 管理员帐户,但出现错误:
Update: Tanakie's code works! This is great! However, I'm only able to get it working in my personal account. I have two G-Suite admin accounts and I get the error:
抱歉,目前无法打开文件.
"Sorry, unable to open the file at this time.
请检查地址,然后重试."
Please check the address and try again."
我已经确认这在多个免费的个人 Google 帐户中运行良好.知道为什么在使用付费谷歌帐户时它不起作用吗?
I have confirmed this works fine in multiple free personal google accounts.Any idea why it will not work when using a paid google account?
------- 更新 ------
------- UPDATE ------
如果您收到抱歉,此时无法打开文件"错误,请等待一天,该错误会自行修复.
If you get the "Sorry, unable to open the file at this time" error, wait a day, that error will fix itself.
这是我仅使用 POST 的最终解决方案.就像田池在下面所说的那样.
Here's my final solution only with a POST. Pretty much as Tanaike says below.
谷歌脚本:
function doPost(e) {
var zipFileName = e.parameter.zipFileName
var fileIds = e.parameter.ids.split(",");
return ContentService.createTextOutput(zipping(fileIds, zipFileName));
}
function zipping(fileIds, zipfilename) {
var blobs = [];
var mimeInf = [];
var accesstoken = ScriptApp.getOAuthToken();
fileIds.forEach(function(fileID) {
try {
var file = DriveApp.getFileById(fileID);
var mime = file.getMimeType();
var name = file.getName();
} catch (er) {
return er
}
var blob;
if (mime == "application/vnd.google-apps.script") {
blob = UrlFetchApp.fetch("https://script.google.com/feeds/download/export?id=" + fileID + "&format=json", {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(name);
} else if (~mime.indexOf('google-apps')) {
mimeInf =
mime == "application/vnd.google-apps.spreadsheet" ? ["application/vnd.openxmlformats-officedocument.spreadsheetml.sheet", name + ".xlsx"] : mime == "application/vnd.google-apps.document" ? ["application/vnd.openxmlformats-officedocument.wordprocessingml.document", name + ".docx"] : mime == "application/vnd.google-apps.presentation" ? ["application/vnd.openxmlformats-officedocument.presentationml.presentation", name + ".pptx"] : ["application/pdf", name + ".pdf"];
blob = UrlFetchApp.fetch("https://www.googleapis.com/drive/v3/files/" + fileID + "/export?mimeType=" + mimeInf[0], {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(mimeInf[1]);
} else {
blob = UrlFetchApp.fetch("https://www.googleapis.com/drive/v3/files/" + fileID + "?alt=media", {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(name);
}
blobs.push(blob);
});
var zip = Utilities.zip(blobs, zipfilename);
var driveFolder = DriveApp.getFoldersByName("zipFiles").next();
return driveFolder.createFile(zip).getId();
}
调用它的php代码:
$url = 'https://script.google.com/a/domain.com/macros/s/### script id ####/exec';
$googleIDs = array();
foreach($documents AS $document){
$googleIDs[] = $document->google_file_id;
}
$data['zipFileName'] = date('c') . ".zip";
$data['ids'] = join(',', $googleIDs);
$ch = curl_init();
curl_setopt($ch, CURLOPT_HTTPHEADER, array( "Content-type: multipart/form-data" ));
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
$result = curl_exec($ch); // This returns the Google file ID of the zip file.
curl_close($ch);
但是,正如我在下面的评论中一样,这是一个无用的、徒劳的练习,因为 Google 将脚本创建的文件限制为 10M.我要去寻找一个不依赖于 Google 的解决方案...希望我在开始之前就知道这一点.
HOWEVER, As in my comment below, this was a useless, futile exercise as Google limits files created by scripts to 10M. I'm off to find a solution that does not depend on Google... Wish I'd known that before I started.
推荐答案
这个解决方法怎么样?
很遗憾,Google API 中没有用于直接从外部创建 zip 文件的 API.但我认为有一个解决方法.Google Apps Script (GAS) 中有 Class Utilities 的 zip()
方法.并且有 Web 应用程序作为从外部使用 GAS 的服务.我认为你想做的事情可以通过结合它们来实现.
Unfortunately, there are no APIs for directly creating a zip file from outside in Google APIs. But I think that there is a workaround. There is zip()
method of Class Utilities in Google Apps Script (GAS). And there is Web Apps as a service for using GAS from outside. I think that what you want to do can be achieved by combining them.
- 使用 Class Utilities 的
zip()
方法创建用于创建 zip 文件的 GAS 脚本. - 将脚本部署为 Web 应用程序.
- 您可以使用应用程序的 GET 和 POST 方法从外部启动脚本.访问 Web Apps 时,也可以提供一些参数和数据.
- Create a GAS script for creating zip files using
zip()
method of Class Utilities. - Deploy the script as Web Apps.
- You can launch the script from outside using GET and POST method of your applications. When you access Web Apps, also you can give some parameters and data.
参考:
- 类实用程序中的 zip() 方法
- 网络应用
- 当电子表格、文档和幻灯片的 Google Docs 包含在文件夹中时,它们将分别转换为 Excel、Word 和 Powerpont 格式.
- 当文件夹中包含独立脚本时,它们会转换为文本数据.
- 其他类型(图片、文本数据等)不转换.
- 将示例脚本复制并粘贴到脚本编辑器中.并保存它.
- 部署网络应用
- 在脚本编辑器上
- 发布 -> 部署为网络应用
- 在项目版本"中,创建新版本.
- 在将应用执行为:"中,选择我".
- 在谁有权访问该应用:"中,选择任何人,甚至是匿名的".
- 点击部署按钮.
- 在脚本编辑器上
- 如果能得到创建的zip文件的文件ID,说明脚本有效.
如果这对你没有用,我很抱歉.
If this was not useful for you, I'm sorry.
下面的示例脚本怎么样?这是一个简单的示例脚本,用于为文件夹中的文件创建 zip 文件.
How about a following sample script? This is a simple sample script for creating a zip file for files in a folder.
这些与网页界面相同.
请执行以下流程.
示例脚本:
function doGet(e) {
var files = DriveApp.getFolderById(e.parameter.folderid).getFiles();
var fileIds = [];
while (files.hasNext()) {
fileIds.push(files.next().getId());
}
return ContentService.createTextOutput(zipping(fileIds));
}
function zipping(fileIds) {
var zipfilename = "sample.zip";
var blobs = [];
var mimeInf = [];
var accesstoken = ScriptApp.getOAuthToken();
fileIds.forEach(function(e) {
try {
var file = DriveApp.getFileById(e);
var mime = file.getMimeType();
var name = file.getName();
} catch (er) {
return er
}
var blob;
if (mime == "application/vnd.google-apps.script") {
blob = UrlFetchApp.fetch("https://script.google.com/feeds/download/export?id=" + e + "&format=json", {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(name);
} else if (~mime.indexOf('google-apps')) {
mimeInf =
mime == "application/vnd.google-apps.spreadsheet" ? ["application/vnd.openxmlformats-officedocument.spreadsheetml.sheet", name + ".xlsx"] : mime == "application/vnd.google-apps.document" ? ["application/vnd.openxmlformats-officedocument.wordprocessingml.document", name + ".docx"] : mime == "application/vnd.google-apps.presentation" ? ["application/vnd.openxmlformats-officedocument.presentationml.presentation", name + ".pptx"] : ["application/pdf", name + ".pdf"];
blob = UrlFetchApp.fetch("https://www.googleapis.com/drive/v3/files/" + e + "/export?mimeType=" + mimeInf[0], {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(mimeInf[1]);
} else {
blob = UrlFetchApp.fetch("https://www.googleapis.com/drive/v3/files/" + e + "?alt=media", {
method: "GET",
headers: {"Authorization": "Bearer " + accesstoken},
muteHttpExceptions: true
}).getBlob().setName(name);
}
blobs.push(blob);
});
var zip = Utilities.zip(blobs, zipfilename);
return DriveApp.createFile(zip).getId();
}
curl 命令示例:
curl -L "https://script.google.com/macros/s/#####/exec?folderid=### folder ID ###"
注意:
- 如果您修改了脚本,请将 Web 应用程序重新部署为新版本.这样就可以反映最新的脚本.
- 作为示例脚本的限制,此示例脚本仅检查文件夹中的文件.如果要检索文件夹中的文件夹,可以查看示例脚本这里.
- 得到创建的 ZIP 文件的文件 ID 后,就可以使用 Drive API 下载了.
如果这对你有用,我很高兴.
If this was useful for you, I'm glad.
这篇关于有没有办法使用 API 从谷歌驱动器上的多个文件创建一个 zip 文件?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!