本文介绍了改变正态分布或高斯分布的标准差(faq 13.20)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

亲爱的,


我只是有一个非常简短的问题。在FAQ列表问题13.20中提到

以下文字:

"这些方法都生成平均值为0且标准差为的数字

1 。(要调整到其他一些分布,乘以标准的

偏差并加上均值。)


你能不能告诉我,哪个数字我必须乘以

标准差?


非常感谢!

解决方案



我非常想说42。在这里......但是......


这些方法产生的数字具有特定的分布 -

对吗?


要更改该分布,您可以按照所需的标准差简单地将它们(

方法生成的数字),并添加

所需的均值 - 可以''你呢?





如果你回复我的帖子,那将是有帮助和礼貌的

至少引用它的相关部分。



....



我之前说过: -

"这些方法产生的数字具有特定的分布 -

对吗?


要更改该分布,您可以按所需的标准差简单地(

方法生成的数字),并添加

必需的意思 - 不是吗? 


你怎么理解这个?


让我们尝试另一种方法。常见问题解答说

这些方法都生成数字,均值为0,标准差为

1.(要调整到其他分布,请乘以标准

偏差并加上均值。)


无论您使用哪种方法生成您的随机数,此指令必须适用,所以它不得以任何方式与该随机数生成器的内部实现相关 - 对吧?


所以我们唯一可以应用这些指令乘以

标准差并加上平均值是随机

数字生成器的输出。那是否更清楚?


DEAR ALL,

I just have a very short question. In the FAQ list question 13.20 the
following text is mentioned:
"These methods all generate numbers with mean 0 and standard deviation
1. (To adjust to some other distribution, multiply by the standard
deviation and add the mean.)"

Could you please let me know, which number I have to multiply with the
standard deviation?

Thanks a lot!

解决方案

I''m sorely tempted to say "42" here... But ...

The numbers generated by these methods have a specific distribution -
right?

To change that distribution, you can simply them (the numbers the
methods generate) by the required standard deviation, and add the
required mean - can''t you?



If you are replying to my posting, it would be helpful and polite to
quote at least the relevant parts of it.

....

I said before :-
"The numbers generated by these methods have a specific distribution -
right?

To change that distribution, you can simply them (the numbers the
methods generate) by the required standard deviation, and add the
required mean - can''t you?"

What about that didn''t you understand?

Let''s try another approach. The FAQ said
"These methods all generate numbers with mean 0 and standard deviation
1. (To adjust to some other distribution, multiply by the standard
deviation and add the mean.)"

This instruction must apply no matter which method you used to
generate your random number, so it must not relate in any way to the
internal implementation of that random number generator - right?

So the only thing to which we can apply the instructions "multiply by
the standard deviation and add the mean" is the output of the random
number generator. Is that any clearer?


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09-17 07:40