问题描述
我想使用HttpURLConnection进行POST。
我正在尝试这两种方式,但我总是在做的时候得到一个例外: conn.getOutputStream();
I want to make a POST by using HttpURLConnection.I am trying this in 2 ways, but I always get an excetion when doing: conn.getOutputStream();
我在两种情况下得到的例外是:
The exception I get in both cases is:
function1:
function1:
public void makePost(String title, String comment, File file) {
try {
URL servlet = new URL("http://" + "www.server.com/daten/web/test/testupload.nsf/upload?CreateDocument");
HttpURLConnection conn=(HttpURLConnection)servlet.openConnection();
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setUseCaches(false);
String boundary = "---------------------------7d226f700d0";
conn.setRequestProperty("Content-type","multipart/form-data; boundary=" + boundary);
//conn.setRequestProperty("Referer", "http://127.0.0.1/index.jsp");
conn.setRequestProperty("Cache-Control", "no-cache");
OutputStream os = conn.getOutputStream(); //exception throws here!
DataOutputStream out = new DataOutputStream(os);
out.writeBytes("--" + boundary + "\r\n");
writeParam(INPUT_TITLE, title, out, boundary);
writeParam(INPUT_COMMENT, comment, out, boundary);
writeFile(INPUT_FILE, file.getName(), out, boundary);
out.flush();
out.close();
InputStream stream = conn.getInputStream();
BufferedInputStream in = new BufferedInputStream(stream);
int i = 0;
while ((i = in.read()) != -1) {
System.out.write(i);
}
in.close();
} catch (Exception e) {
e.printStackTrace();
}
}
或功能2:
public void makePost2(String title, String comment, File file) {
File binaryFile = file;
String boundary = Long.toHexString(System.currentTimeMillis()); // Just generate some unique random value.
URLConnection connection = null;
try {
connection = new URL("http://" + "www.server.com/daten/web/test/testupload.nsf/upload?CreateDocument").openConnection();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
PrintWriter writer = null;
try {
OutputStream output = connection.getOutputStream(); //exception throws here
writer = new PrintWriter(new OutputStreamWriter(output, CHARSET), true); // true = autoFlush, important!
// Send normal param.
writer.println("--" + boundary);
writer.println("Content-Disposition: form-data; name=\""+ INPUT_TITLE +"\"");
writer.println("Content-Type: text/plain; charset=" + CHARSET);
writer.println();
writer.println(title);
// Send binary file.
writer.println("--" + boundary);
writer.println("Content-Disposition: form-data; name=\""+ INPUT_FILE +"\"; filename=\"" + binaryFile.getName() + "\"");
writer.println("Content-Type: " + URLConnection.guessContentTypeFromName(binaryFile.getName()));
writer.println("Content-Transfer-Encoding: binary");
writer.println();
InputStream input = null;
try {
input = new FileInputStream(binaryFile);
byte[] buffer = new byte[1024];
for (int length = 0; (length = input.read(buffer)) > 0;) {
output.write(buffer, 0, length);
}
output.flush(); // Important! Output cannot be closed. Close of writer will close output as well.
} catch (IOException e) {
e.printStackTrace();
} finally {
if (input != null) try { input.close(); } catch (IOException logOrIgnore) {}
}
writer.println(); // Important! Indicates end of binary boundary.
// End of multipart/form-data.
writer.println("--" + boundary + "--");
} catch (IOException e) {
e.printStackTrace();
} finally {
if (writer != null) writer.close();
}
}
推荐答案
无法访问该网址。 URL错误,或DNS服务器无法解析主机名。尝试使用众所周知的URL进行简单连接以排除其中一个,例如
The URL simply cannot be reached. Either the URL is wrong, or the DNS server couldn't resolve the hostname. Try a simple connect with a well-known URL to exclude one and other, e.g.
InputStream response = new URL("http://stackoverflow.com").openStream();
// Consume response.
更新按照注释,您需要使用代理服务器进行HTTP连接。您还需要在Java端配置它。在尝试连接到URL之前添加以下行。
Update as per the comments, you're required to use a proxy server for HTTP connections. You need to configure that in the Java side as well. Add the following lines before any attempt to connect to an URL.
System.setProperty("http.proxyHost", "proxy.example.com");
System.setProperty("http.proxyPort", "8080");
在运行期间只执行一次就足够了。
It suffices to do this only once during runtime.
- Java guides - Networking and proxies
这篇关于HttpURLConnection POST,conn.getOutputStream()抛出异常的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!