执行代码时如何在第一次停止运行spring批处理计划作业?

问题描述

我正在使用带有石英的 spring 批处理 2.2.4 在特定时间运行一些作业

i'm using spring batch 2.2.4 with quartz to run some jobs at certain time

问题是作业总是在第一次执行代码后运行，然后根据预定时间运行.我想停止第一次运行，让它只根据预定时间运行.

the problem is the jobs always run after executing the code at the first time then it runs based on the scheduled time. I want to stop the first run and let it only runs based on the scheduled time.

我的 cron 表达式是0 0 0 * * ?"&我也试过0 0 0 1/1 * ? *"但它在应用程序启动时仍然执行一次

my cron expression is "0 0 0 * * ?" & I also tried "0 0 0 1/1 * ? *" but it still executes once when the application starts

如何在应用程序启动时停止第一次执行?

how can I stop the first execution when the application starts?

这是作业上下文文件:

<batch:job id="exceptionLogJob">
        <batch:step id="exceptionLogReadWriteStep">
            <batch:tasklet >
                <batch:chunk reader="exceptionLogReader" writer="exceptionLogWriter"
                    commit-interval="1000" />
            </batch:tasklet>
        </batch:step>
    </batch:job>


    <!-- ======================================================= -->
    <!-- READER -->
    <!-- ======================================================= -->
    <bean id="exceptionLogReader"
        class="org.springframework.batch.item.database.JdbcCursorItemReader">
        <property name="dataSource" ref="dataSource" />
        <property name="sql" value="SELECT a.*,a.rowid FROM SF_EXCEPTION_LOG a WHERE DATETIME  > SYSDATE - 1" />
        <property name="rowMapper" ref="ExceptionLogRowMapper" />
    </bean>
    <!-- ======================================================= -->
    <!-- Writer -->
    <!-- ======================================================= -->
    <bean id="exceptionLogWriter"
        class="com.mobily.sf.batchprocessor.exceptionlog.ExceptionLogWriter" />

            <bean id="jobDetailExceptionLog" class="org.springframework.scheduling.quartz.JobDetailBean">
        <property name="jobClass"
            value="com.sf.batchprocessor.commons.JobLauncherDetails" />
        <property name="jobDataAsMap">
            <map>
                <entry key="jobName" value="exceptionLogJob" />
                <entry key="jobLocator" value-ref="jobRegistry" />
                <entry key="jobLauncher" value-ref="jobLauncher" />
            </map>
        </property>
    </bean>

    <bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
        <property name="triggers">
            <bean id="cronTrigger"
                class="org.springframework.scheduling.quartz.CronTriggerFactoryBean">
                <property name="jobDetail" ref="jobDetailExceptionLog" />
                <property name="cronExpression" value="0 0 0 1/1 * ? *" />
            </bean>
        </property>
    </bean>

</beans>

推荐答案

我遇到了同样的问题，确定是 Spring boot 的自动配置服务引起的.默认情况下，它将在应用程序启动后运行所有配置的作业 bean.

I had the same problem and determined that it was caused by Spring boot's autoconfiguration service. By default, it will run all configured job beans after application start.

有两个属性会影响此行为:

There are two properties that affect this behavior:

• spring.batch.job.enabled
• spring.batch.job.names

当设置为 false 时，第一个会阻止启动所有作业.第二个接受将运行的作业名称的逗号分隔列表.

The first prevents the launching of all jobs when set to false. The second accepts a comma-delimited list of job names that will be run.

这两个属性可以通过多种方式设置Spring 启动文档:

These two properties can be set a variety of ways specified in the Spring boot docs:

1. 命令行(--spring.batch.job.enabled=false)
2. Java 系统属性(-Dspring.batch.job.enabled=false)
3. 操作系统环境变量
4. @PropertySource 注释
5. jar 目录下的application.properties 文件
6. jar 内的application.properties 文件
7. SpringApplication.setDefaultProperties

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