使用jenkins中的循环构建流程插件的并行作业

问题描述

我使用构建流程插件构建jenkins流程，该流程插件将抓取所有作业，将该名称与正则表达式进行比较，如果匹配，则会触发作业构建。

I完美的工作：

    parallel 取一个闭包列表，所以你应该能够使用 collect 返回一个列表：
  import jenkins.model。 Jenkins 
 import java.util.regex。* 
 
模式myRegex =〜/ release_status。* / 
并行jenkins.model.Jenkins.instance.items.collect {item  - > ; 
 { - > 
 if（item.name ==〜myRegex）{
 build（$ item.name）
} 
} 
} 
  
如果名称通过，只返回一个Closure（而不是每个项目的闭包，其中很多项目会提前结束）是： 
 
 
  import jenkins.model.Jenkins 
 import java.util.regex。* 
 
 Pattern myRegex =〜/ release_status。* / 
 
 parallel Jenkins.instance.items.findAll {item  - > item.name ==〜myRegex} 
 .collect {item  - > { - > build（$ item.name）}} 
  
 
I am building a jenkins flow using the build flow plugin that will grab all of the jobs, compare the name to a regex, and if it matches it will trigger a build of the job.
I have this working perfectly:  
import jenkins.model.Jenkins
import java.util.regex.*
Pattern myRegex = ~/release_status.*/
for (item in jenkins.model.Jenkins.instance.items)
{
  if (item.name ==~ myRegex) {
    build( "$item.name" )
  }
}
However this takes a very long time to build all of the matching jobs (right now there are 20 but there could be many more).
I am trying to make this run each job in parallel but I can't figure out the groovy syntax.
I have tried 3 different ways:  
import jenkins.model.Jenkins
import java.util.regex.*
Pattern myRegex = ~/release_status.*/
parallel (
  {
    for (item in jenkins.model.Jenkins.instance.items)
    {
      if (item.name ==~ myRegex) {
        build( "$item.name" )
      }
    }
  }
)
^^This still works, however it works the same way as before. It goes one job at a time and does not build the next until the previous one finishes.  
import jenkins.model.Jenkins
import java.util.regex.*
Pattern myRegex = ~/release_status.*/
parallel (
  {
    for (item in jenkins.model.Jenkins.instance.items)
    {
      if (item.name ==~ myRegex) {
        { build( "$item.name" ) },
      }
    }
  }
)
^^This errors with  
Script1.groovy: 9: Ambiguous expression could be either a parameterless closure expression or an isolated open code block;
   solution: Add an explicit closure parameter list, e.g. {it -> ...}, or force it to be treated as an open block by giving it a label, e.g. L:{...} @ line 9, column 9.
           { build( "$item.name" ) },
break
import jenkins.model.Jenkins
import java.util.regex.*
Pattern myRegex = ~/release_status.*/
parallel (
  [
    for (item in jenkins.model.Jenkins.instance.items)
    {
      if (item.name ==~ myRegex) {
        useless: { build( "$item.name" ) },
      }
    }
  ]
)
break
import jenkins.model.Jenkins
import java.util.regex.*
Pattern myRegex = ~/release_status.*/
parallel (
    for (item in jenkins.model.Jenkins.instance.items)
    {
      if (item.name ==~ myRegex) {
        { build( "$item.name" ) },
      }
    }
)
Both of the blocks above error with the following:
org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed:
Script1.groovy: 5: unexpected token: for @ line 5, column 5.
       for (item in jenkins.model.Jenkins.instance.items)
A lot of code here but its fairly simple. Looking around I can't find many good resources on groovy.  
 解决方案 
parallel takes a list of Closures, so you should be able to use collect to return a list:
import jenkins.model.Jenkins
import java.util.regex.*

Pattern myRegex = ~/release_status.*/
parallel jenkins.model.Jenkins.instance.items.collect { item ->
    { ->
        if (item.name ==~ myRegex) {
            build( "$item.name" )
        }
    }
}
An alternative that only returns a Closure if the name passes (rather than a Closure for every item, a lot of which will finish early) is:
import jenkins.model.Jenkins
import java.util.regex.*

Pattern myRegex = ~/release_status.*/

parallel Jenkins.instance.items.findAll { item -> item.name ==~ myRegex}
                               .collect { item -> { -> build("$item.name") } }
                        
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