问题描述
有没有什么方法可以捕捉因右移而发生的损失位
运营商？
例如
int a = 5;
a = a> 1; // // a现在为2，最低有效位丢失//
//
我想要这个问题的解决方案：
"如何仅使用<<<<"来查找数字是偶数还是奇数或/和>>"
运营商？"
Hi,
Is there any way to catch the losing bit occurring due to Right Shift
Operator ?
e.g
int a = 5 ;
a = a >1 ; // // a is now 2 and the least significant bit is lost //
//
I want this solution for the question:
"How to find if the number is even or odd using only "<<" or/and ">>"
operators ?"
推荐答案
int a = 5;
int lost_bit = a& 1;
a = a> 1;
/ *现在lost_bit保留丢失的位* /
int a = 5;
int lost_bit = a & 1;
a = a >1;
/* now lost_bit holds the lost bit */
我们不会为你做功课。继续思考。
-Arthur
We won''t do your homework for you. Keep thinking.
-Arthur
也许，我不清楚我的问题。
我的意思是我们不应该使用任何其他按位运算符其他
比<<"或>>。
"&"不允许使用。
Perhaps, i was not clear about my question.
I meant we are not supposed to use any other bitwise operators other
than "<<" or ">>".
"&" operator is not allowed.
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