问题描述
我有两个字符串数组。有一个简短的名称。
I have two String arrays. One having short name.
// days short name
String[] shortNames = {"SUN", "MON", "...", "SAT"};
另外有长的名字。
The other having long name.
// days long name
String[] longNames = {"SUNDAY", "MONDAY", "....", "SATURDAY"};
双方有相同数目的元素。我该如何映射短名作为关键字和长名称作为HashMap的价值？
Both having same number of elements. How can I map short name as KEY and long name as VALUE in HashMap?
HashMap<String, String> days = new HashMap<>();
我知道，我可以通过循环使。有没有更好的办法？
I know, I can make by looping. Is there a better way?
推荐答案
有很多方法可以做到这一点。一说是相当容易理解和使用的Java 8流和收藏家，从指数的关键值对的流图适用于：
There are lots of ways you can do this. One that is fairly easy to understand and apply is using Java 8 streams and collectors to map from a stream of indices to key value pairs:
Map<String, String> days = IntStream.range(0, shortNames.length)
.collect(Collectors.toMap(i -> shortNames[i], i -> longNames[i]));
有，包括一个拉链功能采取两个流，并从一个到另一个产生地图一些第三方Java库。但实际上它们是实现同样的事情code以上只是简洁的方式。
There are some third party Java libraries that include a 'zip' function to take two streams and produce a map from one to the other. But really they are just neater ways of achieving the same thing as the code above.
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