问题描述
我想使用 div>
生成所有提交的列表,将包含违规模式的日志消息减去,并将结果以您所需的选项提供给 git log 。在最后阶段, git log 的选项很方便: - stdin
除了命令行中列出的 commit 之外,还可以从标准输入中读取它们。
- 不散步
只显示给定的转速,但不要穿越他们的祖先。
您可以通过一个管道和流程替换来完成它。
#! / bin / bash
if(($#< 1));然后
echo>& 2用法:$ 0 pattern [< since> ..< until>]
exit 1
fi
pattern = $ 1
转换
git log --format =%H $ @ |
grep -v -f git log --pretty --stat --stdin --no-walk
如果你不想使用bash,你可以用Perl来完成它。
#! / usr / bin / env perl
use strict;
使用警告;
没有警告exec;
sub usage {Usage:$ 0 pattern \\\
}
sub commits_to_omit {
my($ pattern)= @_;
打开我的$ fh, - |,git,log,--grep = $ pattern,--format =%H,@ARGV
或死于$ 0:exec:$!;
my%omit = map +($ _ => 1),< $ fh>;
%省略;
}
除非@ARGV> = 1;
my $ pattern = shift;
my%omit = commits_to_omit $ pattern;
打开我的$ all, - |,git,log,--format =%H,@ARGV
或者死掉$ 0:exec:$! ;
打开我的$ out,| - ,git,log,--pretty,--stat,--stdin,--no-walk
或死亡$ 0:exec:$!; $(< $ all>){
print $ out $ _除非$ omit {$ _};
;
$ / code>
假设上面的一个在PATH中是 git-log-vgrep 和一个形式的历史记录
$ git lola
* b0f2a28(tmp,feature1 )D
* 68f87b0 C
* d311c65 B
* a092126 A
| * 83052e6(HEAD,origin / master,master)Z
| * 90c3d28 Y
| * 4165a42 X
| * 37844cb W
| /
* f8ba9ea V
我们可以说
$ git log-vgrep X
可以获得Z,Y,W和V.
你也可以登录其他分支,所以
$ git log-vgrep一个tmp
给出D,C,B和V;和
$ git log-vgrep C tmp〜2..tmp
产量只有D。
以上实现的一个限制是,如果您使用匹配所有提交的模式,例如, 。或 ^ ,那么您将获得HEAD。这就是 git log 的工作方式:
$ git log --stdin --no-walk - -pretty = oneline< / dev / null
83052e62f0dc1c6ddfc1aff3463504a4bf23e3c4 Z
I want to use git log to show all commits that do not match a given pattern. I know I can use the following to show all commits that do match a pattern:
git log --grep=<pattern>
How do I invert the sense of matching?
I am trying to ignore commits that have "bumped to version ..." in the message.
EDIT: I want my final output to be pretty verbose. e.g. git log --pretty --stat. So output from git log --format=oneline won't work for me.
Generate a list of all commits, subtract those whose log messages contain the offending pattern, and feed the result to git log with your desired options. In the final stage, a couple of options to git log are handy:
You can do it with a single pipeline and process substitution.
#! /bin/bash if (( $# < 1 )); then echo >&2 "Usage: $0 pattern [<since>..<until>]" exit 1 fi pattern=$1 shift git log --format=%H $@ | grep -v -f <(git log --format=%H "--grep=$pattern" $@) | git log --pretty --stat --stdin --no-walk
If you don't want to use bash, you could do it with Perl.
#! /usr/bin/env perl use strict; use warnings; no warnings "exec"; sub usage { "Usage: $0 pattern\n" } sub commits_to_omit { my($pattern) = @_; open my $fh, "-|", "git", "log", "--grep=$pattern", "--format=%H", @ARGV or die "$0: exec: $!"; my %omit = map +($_ => 1), <$fh>; %omit; } die usage unless @ARGV >= 1; my $pattern = shift; my %omit = commits_to_omit $pattern; open my $all, "-|", "git", "log", "--format=%H", @ARGV or die "$0: exec: $!"; open my $out, "|-", "git", "log", "--pretty", "--stat", "--stdin", "--no-walk" or die "$0: exec: $!"; while (<$all>) { print $out $_ unless $omit{$_}; }
Assuming one of the above is in your PATH as git-log-vgrep and with a history of the form
$ git lola * b0f2a28 (tmp, feature1) D * 68f87b0 C * d311c65 B * a092126 A | * 83052e6 (HEAD, origin/master, master) Z | * 90c3d28 Y | * 4165a42 X | * 37844cb W |/ * f8ba9ea V
we could say
$ git log-vgrep X
to get Z, Y, W, and V.
You can also log other branches, so
$ git log-vgrep A tmp
gives D, C, B, and V; and
$ git log-vgrep C tmp~2..tmp
yields just D.
One limitation of the above implementations is if you use a pattern that matches all commits, e.g., . or ^, then you'll get HEAD. This is how git log works:
$ git log --stdin --no-walk --pretty=oneline </dev/null 83052e62f0dc1c6ddfc1aff3463504a4bf23e3c4 Z
这篇关于如何取消`git log --grep =< pattern>`或如何显示不符合模式的git日志的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!