JavaMail的ISO-8859-1格式化

本文介绍了JavaMail的ISO-8859-1格式化的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我做了一个电子邮件客户端Android手机在JavaMail API。如果我试图让发件人的mail地址和收件人邮寄下列方法地址：

 地址[] =弗罗马m.getFrom（）;
        从= InternetAddress.toString（弗罗马）字符串;        地址[] = TOA m.getRecipients（Message.RecipientType.TO）;
        字符串= InternetAddress.toString（TOA）;

我得到这样回字符串：

乔治·=？ISO-8859-1 Q + SP = E4the？=
并且它必须是乔治花苞或乔治Spaethe

我认为问题是，这是与其他编码的德国邮件。任何人可以帮助我解决这个问题？

解决方案

MIME头都设有codeD根据的，因此，你需要先取消code它们。

 字符串德codeD = MimeUtility.de codeTEXT（乔治·= ISO-8859-1 Q SP = E4the =？？？？）;

JDK导入：

 进口javax.mail.internet.MimeUtility;

有关Android的：

 进口com.android.email.mail.internet;

参见的Javadoc / p>

I made an E- Mail Client for my Android phone with the Javamail Api. If I try to get the sender's mail adress and the recipients mail adress with the following methods:

Address[] froma = m.getFrom();
        String from = InternetAddress.toString(froma);

        Address[] toa = m.getRecipients(Message.RecipientType.TO);
        String to = InternetAddress.toString(toa);

I get a String like this back:

"Georg =?ISO-8859-1?Q?SP=E4the?=and it has to be Georg Späthe or Georg Spaethe.

I think the Problem is that this are German Mails with another encoding. Can anybody help me to solve that Problem?

解决方案

MIME headers are encoded as per RFC 2047, therefore you need to decode them first.

String decoded = MimeUtility.decodeText("Georg =?ISO-8859-1?Q?SP=E4the?=");

JDK import:

import javax.mail.internet.MimeUtility;

For Android:

import com.android.email.mail.internet;