如何在 Android 中以 XML 格式发送 SOAP 请求和解析 SOAP 响应?

问题描述

我对 Android 应用开发非常陌生.在我的新 Android 应用程序中，我想显示一些来自 web 服务的数据.这意味着我有一个 SOAP 消息，我需要解析来自 SOAP 响应的数据.在 iPhone 应用程序中，我非常了解解析 SOAP 消息响应，但是在 android 中我不知道该怎么做?我在谷歌上搜索了很多并得到了一些想法.但是，我对此非常困惑.谁能建议任何最简单的方法来理解 SOAP 发送请求/接收响应并解析(XML 格式)Android 中SAXParser 中的响应?我在我的项目中安装了 ksoap2-android-assembly-2.6.0-jar-with-dependencies.jar.在这里我找到了一些示例代码，我在这里发布，

Am very new to Android apps development. In my new Android app i want to show some data from webservice. This means i have a SOAP message, i need to parse the data from SOAP response. In iPhone app i knew very well to parse SOAP message response but, in android i don't know how to do this? I searched lot in Google and get some ideas. But, am very confusing on this. Can anyone please suggest any easiest way to understand SOAP send request/receive response and parse(XML format) the response in SAXParser in Android? I has installed ksoap2-android-assembly-2.6.0-jar-with-dependencies.jarin my project. Here i found some sample code, i post here,

import java.io.*;
import org.ksoap2.SoapEnvelope;
import org.kxml2.io.KXmlParser;
import org.xmlpull.v1.XmlPullParserException;


public class ParsingSteps
{
  public static void main(String[] args)
   {
     try{
       // String msg="<hello>World!</hello>";
        String msg = "<SOAP-ENV:Envelope " + "xmlns:SOAP-ENV="http://
www.w3.org/2001/12/soap-envelope" " + "xmlns:xsi="http://www.w3.org/
 2001/XMLSchema-instance <http://www.w3.org/%0A2001/XMLSchema-instance>""
 +"xmlns:xsd="http://www.w3.org/2001/
 XMLSchema"& gt;" +
         "<SOAP-ENV:Body>" +
         "<result>" +
         "<message xsi:type="xsd:string">Hello World</message>" +
        "</result>" +
        "</SOAP-ENV:Body>" +
        "</SOAP-ENV:Envelope>";

      //  byte[] in= msg.getBytes();

        KXmlParser parser=new KXmlParser();
       parser.setInput(new StringReader(msg));
       SoapEnvelope soapenvelope= new SoapEnvelope
(SoapEnvelope.VER12);
        //soapenvelope.parse(parser);
        soapenvelope.parseBody(parser);

          }
       catch (IOException e) {
               System.out.println("Error reading URI: " + e.getMessage ());
       } catch (XmlPullParserException e) {
              System.out.println("Error in parsing: " + e.getMessage ());
       }
      //  String result=parser.getName();
       //System.out.println(result);
    }
 }

这是正确的代码.请对我的问题提出任何建议.请帮助我.提前致谢.

Is this correct code. Please give any suggestion on my question. Please help me on this. Thanks in advance.

推荐答案

Google for Ksoap2 教程你会得到很多.这是发送请求到网络服务的示例代码.

Google for Ksoap2 tutorial u will get a lot of them . Here is sample code for sending request to web service .

public class WebServicePoc extends Activity{
private static final String SOAP_ACTION = "http://tempuri.org/Arnoid";
private static final String METHOD_NAME = "Arnoid";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://ipaddress:port/UserAuthenticationInterfacer.asmx";
EditText editText;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    HashMap<String, String> a=new HashMap<String, String>();
    try {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("FOSID", "1994");
        request.addProperty("IMEINumber", "");
        request.addProperty("SIMCardNo", "");
        request.addProperty("ApplicationName", "App");
        request.addProperty("CurrentVersion", "1.0.0.0");
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);
        AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);
        SoapObject result = (SoapObject)envelope.getResponse();
        editText=(EditText)findViewById(R.id.text1);
        editText.setText(result.toString());
    } catch (Exception e) {
        e.printStackTrace();
    }

对于 xml，请检查 xml 解析器的教程，仅使用 SAX，因为 android 不支持 STAX.对于发送 xml 请求，您可以将 xml 作为字符串发送，然后在服务器端解码.

And for xml pls check tutorial for xml parsers,use SAX only, as STAX is not supported in android . For sending xml request u can send xml as string and then decode on sever side .

这篇关于如何在 Android 中以 XML 格式发送 SOAP 请求和解析 SOAP 响应?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！