问题描述
我在C无符号的字符我想在基地10打印的数组,我卡住了。我认为这将在code得到更好的解释,因此,考虑到:
I have an array of unsigned chars in c I am trying to print in base 10, and I am stuck. I think this will be better explained in code, so, given:
unsigned char n[3];
char[0] = 1;
char[1] = 2;
char[2] = 3;
我要打印197121。
I would like to print 197121.
这是微不足道的小基地256阵列。可以简单地1 * 256 ^ 0 + 2 * 256 ^ 1 + 3 * 256 ^ 2。
This is trivial with small base 256 arrays. One can simply 1 * 256 ^ 0 + 2 * 256 ^ 1 + 3 * 256 ^ 2.
然而,如果我的阵列是100字节大,那么这很快成为一个问题。在C中没有整数类型为100字节大,这就是为什么我在存储无符号的字符数组号开始。
However, if my array was 100 bytes large, then this quickly becomes a problem. There is no integral type in C that is 100 bytes large, which is why I'm storing numbers in unsigned char arrays to begin with.
我怎么在基地10高效打印这个数字呢?
How am I supposed to efficiently print this number out in base 10?
我是有点失落。
推荐答案
有没有简单的方法只使用标准C库做。你要么必须自己编写(不推荐)的功能,或使用外部库,如。
There's no easy way to do it using only the standard C library. You'll either have to write the function yourself (not recommended), or use an external library such as GMP.
例如,使用GMP,你可以这样做:
For example, using GMP, you could do:
unsigned char n[100]; // number to print
mpz_t num;
mpz_import(num, 100, -1, 1, 0, 0, n); // convert byte array into GMP format
mpz_out_str(stdout, 10, num); // print num to stdout in base 10
mpz_clear(num); // free memory for num
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