问题描述
rule: [while [not ["--"] skip] some "-"]parse "a-bc----d" [rule ??]
rule: [while [not ["--"] skip] some "-"]parse "a-bc----d" [rule ??]
打印
??: "d"
但是我需要更有效的规则(例如使用to #"-")...
But I need a more efficient rule (e.g. using to #"-")...
t: copy "" append/dup t "." 10000 append t "-..---..--"rule: [while [not ["--"] skip] some "-"]print [delta-time [loop 1000 [parse t [rule] ]]]
t: copy "" append/dup t "." 10000 append t "-..---..--"rule: [while [not ["--"] skip] some "-"]print [delta-time [loop 1000 [parse t [rule] ]]]
=>在我的手机上〜15.4秒
=> ~ 15.4 sec on my phone
rule: [any ["--" break | skip] any "-"]
=>〜8.2秒
rule: [to "--" some "-"](@ sqlab响应)
rule: [to "--" some "-"] (@sqlab response)
=>〜0.3秒
推荐答案
是什么使您无法使用 to 作为
What prevents you to use to as e.g.
rule: [to "--" some "-" x:]
这篇关于重复PARSE规则以匹配至少2个空格的首次出现的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！