本文介绍了如何将JsonNode转换为ObjectNode的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个带有某些数据的com.fasterxml JsonNode对象.我需要对其数据进行一些操作.我用谷歌搜索了答案，但没有得到正确的答案.您能否建议我如何操作JsonNode数据.我还尝试了如下将JsonNode转换为ObjectNode
I have a com.fasterxml JsonNode object with some data. I need to do some manipulation on its data. I googled for answer but didn't got it properly. Can you please suggest me how to manipulate JsonNode data. I have also tried to convert JsonNode to ObjectNode as follows
ObjectNode objectNode = (ObjectNode)filterJson;
但有以下例外....
java.lang.ClassCastException: com.fasterxml.jackson.databind.node.TextNode cannot be cast to
com.fasterxml.jackson.databind.node.ObjectNode
请帮助！
推荐答案
最后，我得到了如下解决方案...
Finally, I got the solution as follows...
JsonNode jsonNode = Json.toJson("Json String");
ObjectNode node = (ObjectNode) new ObjectMapper().readTree(jsonNode.asText());
//perform operations on node
jsonNode = (JsonNode) new ObjectMapper().readTree(node.toString());
或下面的另一个...
or another one as below...
ObjectNode node = (ObjectNode) new ObjectMapper().readTree("Json String")
//perform operations on node
jsonNode = (JsonNode) new ObjectMapper().readTree(node.toString());
但我不知道这是否是好方法?如果有什么比以上更好的地方，请告诉我.谢谢！
but I don't know if this is good approach or not ?If there is any better than above, please let me know.Thank you!
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