Python_编程题集_001_词法解析

1.词法解析：

string模块解：

import string #引用string模块完成解析

def find(s):

    digit = []  #存储数字

    letter = [] #存储字母、拼音

    punctuation = [] #存储符号、空格

    chinese = []    #存储中文

    for i in s:

        if i in string.digits:

            digit.append(i)

        elif i in string.ascii_letters:

            letter.append(i)

        elif i in string.punctuation or i.isspace():

            punctuation.append(i)

        else:

            chinese.append(i)

        print('数字：{}'.format(''.join(digit)))

        print('拼音：{}'.format(''.join(letter)))

        print('符号：{}'.format(''.join(punctuation)))

        print('中文：{}'.format(''.join(chinese)))

正则解：词法分析

import re

def analysis(str):

    ze={"数字":"\\d","拼音":"[a-zA-Z]","汉字":"[\u4e00-\u9fff]"}

    for k,v in ze.items():

        jg=re.findall(v,str)

        print(k + ":" + ''.join(jg))

        str=re.sub(v,'',str)

        print('符号：{0}'.format(str))