Dr. CAN学习笔记-数学基础Ch0-6复数Complex Number
x 2 − 2 x + 2 = 0 ⇒ x = 1 ± i x^2-2x+2=0\Rightarrow x=1\pm i x2−2x+2=0⇒x=1±i
- 代数表达： z = a + b i , R e ( z ) = a , I m ( z ) = b z=a+bi,\mathrm{Re}\left( z \right) =a,\mathrm{Im}\left( z \right) =b z=a+bi,Re(z)=a,Im(z)=b, 分别称为
实部与虚部 - 几何表达： z = ∣ z ∣ cos θ + ∣ z ∣ sin θ i = ∣ z ∣ ( cos θ + sin θ i ) z=\left| z \right|\cos \theta +\left| z \right|\sin \theta i=\left| z \right|\left( \cos \theta +\sin \theta i \right) z=∣z∣cosθ+∣z∣sinθi=∣z∣(cosθ+sinθi)
- 指数表达： z = ∣ z ∣ e i θ z=\left| z \right|e^{i\theta} z=∣z∣eiθ