drizzle lua 数据传递(ngx.location.capture)_MySQL

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经常使用PHP开发的WEB开发人员，刚刚转到NGINX+DRIZZLE开发环境，开始估计会遇到LUA如何获取DRIZZLE+MYSQL返回数据的问题，下面给出我的一些经验。

首先修改NGINX的配置文件

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location /mysql {
set $name $1;
set_quote_sql_str $quote_name $name;
set $sql "SELECT * FROM crawl WHERE id=3";
drizzle_query $sql; drizzle_pass mysql; rds_json on;
}

curl localhost:8080/mysql 返回的结果：[{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]

然后在后面加入：

        location /lua{            content_by_lua '                local res = ngx.location.capture("/mysql")                ngx.say("data: " .. res.body)            ';          } 

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curl localhost:8080/lua 返回的结果：data: [{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]

最后大家也就都能猜到了

        location /luafile {            content_by_lua_file /usr/local/openresty/nginx/html/test.lua;        }

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test.lua

local res = ngx.location.capture("/mysql")ngx.say("data: " .. res.body)

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搞定：curl localhost:8080/luafile 返回的结果：data: [{"id":3,"url_id":"100","url_type":"item","date":"0000-00-00","url":"http://item.taobao.com/item.htm?id=100","status":0,"failures":0,"start_date":0,"unit_id":54848}]

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