题目
解题思路
- 双层循环,三个条件依次判断,进行累加记录。
代码展示
public class Zero {
public static void main(String[] args) {
Zero zero = new Zero();
System.out.println(zero.longestAlternatingSubarray(new int[]{3,2,5,4}, 5));
System.out.println(zero.longestAlternatingSubarray(new int[]{1,2}, 2));
System.out.println(zero.longestAlternatingSubarray(new int[]{2,3,4,5}, 4));
}
public int longestAlternatingSubarray(int[] nums, int threshold) {
int ans = 0;
for (int i = 0; i < nums.length; i++){
if(nums[i] % 2 != 0 || nums[i] > threshold){
continue;
}
int count = 1;
for (int j = i + 1; j < nums.length; j++){
if(nums[j] % 2 == nums[j - 1] % 2){
break;
}
if(nums[j] > threshold){
break;
}
count++;
}
ans = Math.max(ans, count);
}
return ans;
}
}