题目
解题思路
- 将字符串转换成字符数组;
- 遍历字符数组,首位对称字符对比;
- 若不相同则将较小的字符赋值给较大的字符;
代码展示
class Solution {
public String makeSmallestPalindrome(String s) {
char[] chars = s.toCharArray();
int n = chars.length;
for (int i = 0; i < n / 2; i++){
if(chars[i] != chars[n - 1 - i]){
if(chars[i] > chars[n - 1 - i]){
chars[i] = chars[n - 1 - i];
} else {
chars[n - 1 - i] = chars[i];
}
}
}
return new String(chars);
}
}