java - 如何以这种格式编写Java模式:任何字符(int，int)(int，int)数字数字(int，int，int)

例如

Maze0.bmp (0,0) (319,239) 65 120
Maze0.bmp (0,0) (319,239) 65 120 (254,243,90)
Maze0.bmp (0,0) (319,239) 65 120 (254,243,90) (0,0,0)
Maze0.bmp (0,0) (319,239) 65 120 (254,243,90) (0,0,0) (11,33,44)

我想获取maze0.bmp和所有数字。我有：

Pattern pattern = Pattern.compile("([A-z][^\\s]*)\\s+\\((\\d+),(\\d+)\\)\\s+\\((\\d+),(\\d+)\\)\\s+(\\d+)\\s+(\\d+)\\s+(\\((\\d+),(\\d+),(\\d+)\\)\\s*)");
BufferedReader stdin = new BufferedReader(new InputStreamReader( System.in));
String input;
Matcher matcher = null;
boolean isMatched = false;
while (!isMatched) {
    System.out.println("Please enter right format\n");
    input = stdin.readLine();
    matcher = pattern.matcher(input);
    while(matcher.find()) {
        isMatched = true;
        for (int i = 1; i <= matcher.groupCount(); ++i)
            System.out.println(matcher.group(i));
    }
}

没错例如，如果我的输入是

Maze0.bmp (0,0) (319,239) 65 120 (254,243,90) (0,0,0)

它无法获取最后一个元组（0,0,0）。

最佳答案

这是我能想到的最好的。请注意，我使用了两种模式，因为出于某种原因Java拒绝捕获重复的组（如果有人碰巧知道原因，请plz发表评论）。

final Pattern outerPattern = Pattern.compile("(.*?) \\((\\d+),(\\d+)\\) \\((\\d+),(\\d+)\\) (\\d+) (\\d+)(.*)");
final Pattern optionalTouplePattern = Pattern.compile(" \\((\\d+),(\\d+),(\\d+)\\)");

final BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
boolean isMatched;

do
{
    System.out.println("Please enter right format:");
    Matcher m = outerPattern.matcher(stdin.readLine());
    if (isMatched = m.find())
    {
        System.out.println(String.format("name='%s', first touple: [%s,%s], second touple: [%s,%s], first single number: %s, second single number: %s", m.group(1), m.group(2), m.group(3), m.group(4), m.group(5), m.group(6), m.group(7)));
        m = optionalTouplePattern.matcher(m.group(8));
        while(m.find())
        {
            System.out.println(String.format("+ optional touple: [%s,%s,%s]", m.group(1), m.group(2), m.group(3)));
        }
    }
}while(!isMatched);