当我对串行数据使用XML序列化方法时，我发现错误错误2，'consoleapplication3.program.converttoxml< T>（string）'的最佳重载方法匹配有一些无效的参数

问题描述

;有一些无效的论点

public class AddressDetails
    {
        public int HouseNo { get; set; }
        public string StreetName { get; set; }
        public string City { get; set; }
        private string PoAddress { get; set; }
    }



    public T ConvertToXml<T>(string xml)
    {
        var serializer = new XmlSerializer(typeof(T));
        return (T)serializer.Deserialize(new StringReader(xml));
    }


     static void Main(string[] args)
     {


         AddressDetails details = new AddressDetails();
         details.HouseNo = 4;
         details.StreetName = "Rohini";
         details.City = "Delhi";
         ConvertToXml<string>(details);
     }

我的尝试：



公共类AddressDetails

{

public int HouseNo {get;组; }

public string StreetName {get;组; }

public string City {get;组; } $ / $
私有字符串PoAddress {get;组; }

}







public T ConvertToXml< t>（字符串xml）

{

var serializer = new XmlSerializer（typeof（T））;

return（T）serializer.Deserialize（new StringReader（ xml））;

}





static void Main（string [] args）

{





地址详细信息=新地址详细信息（）;

details.HouseNo = 4 ;

details.StreetName =Rohini;

details.City =Delhi;

ConvertToXml< string>（details）;

}

What I have tried:

public class AddressDetails
{
public int HouseNo { get; set; }
public string StreetName { get; set; }
public string City { get; set; }
private string PoAddress { get; set; }
}



public T ConvertToXml<t>(string xml)
{
var serializer = new XmlSerializer(typeof(T));
return (T)serializer.Deserialize(new StringReader(xml));
}


static void Main(string[] args)
{


AddressDetails details = new AddressDetails();
details.HouseNo = 4;
details.StreetName = "Rohini";
details.City = "Delhi";
ConvertToXml<string>(details);
}

推荐答案

using System;
using System.Xml.Serialization;



public class AddressDetails
{
    public int HouseNo { get; set; }
    public string StreetName { get; set; }
    public string City { get; set; }
    private string PoAddress { get; set; }
}

public class MyCLass
{

    public static string ConvertToXml<T>(object xml)
    {

        var stringwriter = new System.IO.StringWriter();
        var serializer = new XmlSerializer(typeof(T));
        serializer.Serialize(stringwriter, xml);
        return stringwriter.ToString();
    } 

    static void Main(string[] args)
    {


        AddressDetails details = new AddressDetails();
        details.HouseNo = 4;
        details.StreetName = "Rohini";
        details.City = "Delhi";
        var xmlString = ConvertToXml<AddressDetails>(details);
        Console.WriteLine(xmlString);
        Console.ReadLine();
    }
}

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