在array_walk（）的回调函数中删除行

问题描述

我正在尝试使用array_walk（）函数使用数组：

I'm trying to work with array using array_walk() function such way:

<?php

$array = array('n1' => 'b1', 'n2' => 'b2', 'n3' => 'b3');

array_walk($array, function(&$val, $key) use (&$array){
    echo $key."\n";
    if ($key == 'n1')
        $val = 'changed_b1';
    if ($key == 'n2' || $key == 'n3') {
        unset($array[$key]);
    }
});

print_r($array);

获取：

n1
n2
Array
(
    [n1] => changed_b1
    [n3] => b3
)

似乎，删除第二个元素之后的情况-第三个元素不会发送到回调函数。

It seems, what after deletion of 2nd element -- 3rd element don't be sended to callback function.

推荐答案

您可以使用辅助数组，该效果将导致那些节点已被删除，例如；

What you can do is use a secondary array, which will give the effect that those nodes have been deleted, like;

<?php

$array = array('n1' => 'b1', 'n2' => 'b2', 'n3' => 'b3');

$arrFinal = array();
array_walk($array, function($val, $key) use (&$array, &$arrFinal){
    echo $key."\n";
    if ($key == 'n2' || $key == 'n3') {
        //Don't do anything
    } else {
       $arrFinal[$key] = $val;
    }
});

print_r($arrFinal);

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