如何对 XSLT 模板的输出进行二次转换

本文介绍了如何对 XSLT 模板的输出进行二次转换的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我只有基本的 XSLT 技能，所以如果这是基本的或不可能的，我深表歉意.

I have only basic XSLT skills so apologies if this is either basic or impossible.

我有一个分页器模板，它在我正在查看的网站上随处可见.存在一个错误，即一个特定的搜索需要将 categoryId 参数附加到页面链接的 href 中.我无法更改分页器样式表，否则我只会向其中添加一个参数.我想做的是按原样应用模板，然后根据其输出进行第二次转换.这可能吗?其他人通常如何扩展库模板?

I have a paginator template which is used everywhere on the site I'm looking at. There's a bug where one particular search needs to have a categoryId parameter appended to the href of the page links. I can't alter the paginator stylesheet or else i would just add a param to it. What I'd like to do is apply the template as is then do a second transform based on its output. Is this possible? How do others normally go about extending library templates?

到目前为止，我已经考虑过对输出进行递归复制，并在处理 hrefs 时将模板应用于它们.它的语法让我有些不知所措，特别是因为我什至不确定这是否可能.

So far I've thought about doing a recursive copy of the output and applying a template to the hrefs as they are processed. The syntax for that escapes me somewhat, particularly as I'm not even sure it's possible.

编辑 - 在 Dabbler 的回答和 Michael Kay 的评论之间，我们到达了那里.这是我的完整测试.

Edit - Between Dabbler's answer and Michael Kay's comment we got there. Here is my complete test.

 <xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common">
    <!-- note we require the extensions for this transform -->

    <!--We call the template to be extended here and store the result in a variable-->
    <xsl:variable name="output1">
            <xsl:call-template name="pass1"/>
    </xsl:variable>

    <!--The template to be extended-->
    <xsl:template name="pass1">
            <a href="url?param1=junk">foo</a>
    </xsl:template>

    <!--the second pass. we lock this down to a mode so we can control when it is applied-->
    <xsl:template match="a" mode="pass2">
            <xsl:variable name="href" select="concat(@href, '&amp;', 'catid', '=', 'stuff')"/>
            <a href="{$href}"><xsl:value-of select="."/></a>
    </xsl:template>

    <xsl:template match="/">
            <html><head></head><body>
                    <!--the node-set extension function turns the first pass back into a node set-->
                    <xsl:apply-templates select="ext:node-set($output1)" mode="pass2"/>
            </body></html>
    </xsl:template>

</xsl:stylesheet>

推荐答案

在 XSLT 2 中是可能的；您可以将数据存储在变量中，然后调用 apply-templates.

It's possible in XSLT 2; you can store data in a variable and call apply-templates on that.

基本示例:

<xsl:variable name="MyVar">
   <xsl:element name="Elem"/> <!-- Or anything that creates some output -->
</xsl:variable>
<xsl:apply-templates select="$MyVar"/>

在你的样式表的某个地方有一个与 Elem 匹配的模板.您还可以使用单独的模式来明确区分两个阶段(构建变量和处理变量)，尤其是当两个阶段都使用匹配相同节点的模板时.

And somewhere in your stylesheet have a template that matches Elem. You can also use a separate mode to keep a clear distinction between the two phases (building the variable and processing it), especially when both phases use templates that match the same nodes.

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