子串，修剪

问题描述

大家好.

我正在尝试使用C#检索电子邮件.我得到了我所需要的一切.但是问题在于消息内容即将来临..

Hi every one.

I am trying to retrieve email by using C#. I got every thing I required. But the problem is the message content is coming like..

--0016367fb7376bfdc30499a12567
Content-Type: text/plain; charset=ISO-8859-1

Your Text message.

--0016367fb7376bfdc30499a12567
Content-Type: text/html; charset=ISO-8859-1

我只需要内容

I need to take only the content

Your Text message.

任何人都可以通过给出逻辑来帮助我，我该如何找回它.
条件是

Can any one please help me out by giving the logic, how can I retrieve it.
The condition is

--0016367fb7376bfdc30499a12567
Content-Type: text/plain; charset=ISO-8859-1

对于不同的邮件可以有所不同，但相同的顺序将是特定顺序的两倍.

在此先感谢.

can be different for different mails but the same will be twice in that particular order.

Thanks in advance.

推荐答案

--0016367fb7376bfdc30499a12567Content-Type: text/plain; charset=ISO-8859-1


A0AKKmasaieTTYYIOIOIMddssPP...--++yyyYYYYYour Text messageA0AKKmasaieTTYYIOIOIMddssPP...--++yyyYYYY


.--0016367fb7376bfdc30499a12567Content-Type: text/html; charset=ISO-8859-1

现在您已经有了字符串的起点和终点，可以很轻松地删除废物.

Now you have start and end point of your string and it will be simple to delete wastes.

private string FixString(string message)
{
    string[] fixedCode =new string[1] {"A0AKKmasaieTTYYIOIOIMddssPP...--++yyyYYYY"};

    StringSplitOptions option = StringSplitOptions.None;
    string[] messages = message.Split(fixedCode, option);
    for (int i = 0; i < messages.Length;i++ )
    {
        if (i == 1)
            return messages[i];
    }

    return string.Empty;

}

现在，您可以找到您的主要信息:

Now, you can find your main message:

string k = @"--0016367fb7376bfdc30499a12567Content-Type: text/plain; charset=ISO-8859-1
Your Text message.A0AKKmasaieTTYYIOIOIMddssPP...--++yyyYYYYHelloA0AKKmasaieTTYYIOIOIMddssPP...--++yyyYYYY--0016367fb7376bfdc30499a12567Content-Type: text/plain; charset=ISO-8859-1
Your Text message.";
           
Console.WriteLine(FixString(k));

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