本文介绍了使用Netty发送POST参数，为什么DefaultHttpDataFactory不在版本中？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
HttpRequest httpReq=new DefaultHttpRequest(HttpVersion.HTTP_1_1,HttpMethod.POST,uri);
httpReq.setHeader(HttpHeaders.Names.HOST,host);
httpReq.setHeader(HttpHeaders.Names.CONNECTION,HttpHeaders.Values.KEEP_ALIVE);
httpReq.setHeader(HttpHeaders.Names.ACCEPT_ENCODING,HttpHeaders.Values.GZIP);
String params="a=b&c=d";
ChannelBuffer cb=ChannelBuffers.copiedBuffer(params,Charset.defaultCharset());
httpReq.setHeader(HttpHeaders.Names.CONTENT_LENGTH,cb.readableBytes());
httpReq.setContent(cb);
不产生有效请求。发送post请求的正确方法是什么，最好是手动构造参数数据而不是DataFactory。另外，为什么HttpDataFactory不包含在任何版本中？
Does not yield a valid request. What is the correct way to send a post request, preferably by constructing the parameters data manually as opposed to with the DataFactory. Also, why is HttpDataFactory not included in any of the releases?
推荐答案
你写的一切都是正确的，只需添加 httpReq.setHeader（HttpHeaders.Names.CONTENT_TYPE，application / x-www-form-urlencoded）;
，您的示例将起作用。对于更复杂的代码，您需要添加url编码。
You wrote everything correct, just add httpReq.setHeader(HttpHeaders.Names.CONTENT_TYPE,"application/x-www-form-urlencoded");and your example will work. For more complex code you need to add url encoding.
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