Hibernate:带有注解动态表名的数据对象

问题描述

我有一个与表相关联的 Hibernate 数据类；想象 Entity Person 像这样:

I have a Data Class for Hibernate associated to a table; imagine the Entity Person like this:

 @Entity
 @org.hibernate.annotations.Proxy(lazy=false)
 @Table(name="Person", schema="MySchema")
 @Inheritance(strategy=InheritanceType.SINGLE_TABLE)
 public class ProfileData implements Serializable {

    private static final long serialVersionUID = -844564646821609090L;

    public PersonData() {
    }

    @Column(name="idPerson", nullable=false, unique=true)   
    @Id 
    ...

我需要按此表的年份创建历史表:Person2010、Person2011、Person2012...是否可以不创建新的数据对象?也许通过参数...?我不知道.

I need to create historic tables by years of this table: Person2010, Person2011, Person2012... Is it possible without creating new Data Objects? Maybe by a parameter...? I don´t know.

Entity 类是一样的，改变了表名和构造函数.

The Entity class is the same, changing the table name and the constructor.

推荐答案

另一种架构，更复杂但更优雅:

Another one Architecture, more complez but elegant:

是，您可以使用NamingStrategies更改表名:

YES, You can change the table names using NamingStrategies:

public class MyNamingStrategy extends DefaultNamingStrategy {
   ...
   @Override
   public  String tableName(String tableName) {
      return tableName+yearSuffixTable;
   }
   ...
}

而且，当您想使用 _year 表时，您必须使用 Hibernate 创建一个会话来覆盖表名:

And, when you wanna to use the _year tables, you must to create a session with Hibernate that override rhe table names:

  SessionFactory sessionFactory;
  Configuration config = new AnnotationConfiguration()
                         .configure("hibernate.cfg.xml")
                         .setNamingStrategy( new MyNamingStrategy () );
  sessionFactory = config.buildSessionFactory();
  session = sessionFactory.openSession();

对于我的架构，我按年创建一个会话并将其存储到应用程序映射中，以便在需要时访问.

For my architecture I create a session by year and store it into Application map for access when I need it.

谢谢.

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