简单Java PriorityQueue< String>错误

问题描述

我要做的就是将三个字符串添加到Java PriorityQueue中，然后将它们打印出来这是我的代码:

All I am doing is add three strings to a Java PriorityQueue and then print them outThis is my code:

import java.util.*;
import java.lang.*;

class Main
{
    public static void main (String[] args) throws java.lang.Exception
    {
        PriorityQueue<String> pq=new PriorityQueue<String>();
        pq.add("abc");
        pq.add("ability");
        pq.add("aberdeen");

        String s="ability";
        System.out.println(s.compareTo("aberdeen"));

        System.out.println(pq);
    }
}

这是输出:

4
[abc, ability, aberdeen]

这不是应该是 abc，阿伯丁，能力.因为那是正确的字母顺序?

Shouldn't this be abc, aberdeen, ability instead. since that's the correct alphabetic order?

推荐答案

来自:

这就是 toString()用来构造字符串表示形式的原因，因为实现是:

That's what toString() is using to construct the string representation, as the implementation is inherited from AbstractCollection:

尝试将结果出队，您将获得预期的顺序:

Try dequeuing the results instead, and you'll get the expected order:

while (pq.size() > 0) {
    System.out.println(pq.poll());
}

输出:

abc
aberdeen
ability

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