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问题描述

我有一个循环的一堆URL,对于每一个我正在做以下:

I have a loop over a bunch of URLs, for each one I'm doing the following:

private String doQuery(String url) {

  HttpGet httpGet = new HttpGet(url);
  setDefaultHeaders(httpGet); // static method
  HttpResponse response = httpClient.execute(httpGet);   // httpClient instantiated in constructor

  int rc = response.getStatusLine().getStatusCode();

  if (rc != 200) {
    // some stuff...
    return;
  }

  HttpEntity entity = response.getEntity();

  if (entity == null) {
    // some stuff...
    return;
  }

  // process the entity, get input stream etc

}

第一个查询是正常的,第二个查询会抛出此异常:

The first query is fine, the second throws this exception:

这只是一个简单的单线程应用程序。如何释放此连接?

This is just a simple single-threaded app. How can I release this connection?

推荐答案

回答我自己的问题:释放连接请求)您必须关闭由HttpEntity返回的InputStream:

To answer my own question: to release the connection (and any other resources associated with the request) you must close the InputStream returned by the HttpEntity:

InputStream is = entity.getContent();

.... process the input stream ....

is.close();       // releases all resources

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10-23 15:37