问题描述
我知道有关于此,我遵循它,但是我必须在我的代码中犯下一个错误,这里是:
function dropAnim(lat,lng,name){
console.log(----+ lat + - + lng);
var marker = new google.maps.Marker({
position:new google.maps.LatLng(lat,lng),
map:map,
title:名称,
动画:google.maps.Animation.DROP,
图标:imageCar,
});
}
var counter = 0;
$ .get('http://server.com/methods.php?m=loadPins',函数(数据){
dataName = data.name.split (;);
dataLat = data.lat.split(;);
dataLng = data.lng.split(;);
dataLength = dataName.length-1;
for(var i = 0; i< dataLength; i ++){
var lat = dataLat [i];
var lng = dataLng [i];
console.log(lat + - + lng);
setTimeout(function(){
dropAnim(lat,lng ,dataName [i]);
},counter * 400);
counter ++;
}
},json);
问题是它在同一个地方加载3个引脚。 dataLat和dataLng加载3倍不同,我可以看到,在控制台中,但是当我看到从insde函数中出来的控制台时,有3个相同的lat和lng(最后一个)。
setTimeout((function( i){
return function(){
dropAnim(dataLat [i],dataLng [i],dataName [i]);
};
})(i),计数器* 400);
你的问题是,当你的超时回调被调用时, i
变量已经具有 dataLength
值,因为您的循环已经在那段时间完成了。
I know there's a question about this Google Maps API v3 drop markers from XML with delay? and I followed it, but I had to made a mistake in my code, here it is:
function dropAnim(lat,lng,name) {
console.log("---- " + lat + " - " + lng);
var marker = new google.maps.Marker({
position: new google.maps.LatLng(lat,lng),
map: map,
title: name,
animation: google.maps.Animation.DROP,
icon: imageCar,
});
}
var counter = 0;
$.get('http://server.com/methods.php?m=loadPins', function(data) {
dataName = data.name.split(";");
dataLat = data.lat.split(";");
dataLng = data.lng.split(";");
dataLength = dataName.length-1;
for(var i=0;i<dataLength;i++) {
var lat = dataLat[i];
var lng = dataLng[i];
console.log(lat + " - " + lng);
setTimeout(function() {
dropAnim(lat,lng,dataName[i]);
}, counter * 400);
counter++;
}
},"json");
The problem is that it loads 3 pins in the exact same place. dataLat and dataLng load 3x times different and I can see that in console, but when I see what comes out in console from insde the function, there are 3 same lat and lng (the last one).
Try like this:
setTimeout((function(i) {
return function(){
dropAnim(dataLat[i],dataLng[i],dataName[i]);
};
})(i), counter * 400);
Your problem was, when your timeout's callback is called, i
variable already has dataLength
value, as your loop is already finished by that time.
这篇关于Google将api v3拖放标记动画延迟映射的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!