问题描述
我很亲近.我正在尝试为 Notepad++ 编写一个正则表达式，用空格替换破折号，忽略 破折号已经带有前/后空格.我意识到我可以用foobarfoo"搜索/替换-"然后搜索-"替换"然后将foobarfoo"转换回-"，但是该死的-我正在尝试学习正则表达式！
I am sooo close. I am trying code a regex expression for Notepad++ to replace a dash with a space, ignoring dashes already with a pre/post space. I realize I could search/replace " - " with "foobarfoo" then search for "-" replacing for " " then converting "foobarfoo" back to " - ", but damnit - I'm trying to learn regex!
这是我的问题:
适配器 - BNC 公头到 BNC 母头，直角
到
适配器 - BNC 公头到 BNC 母头，直角
(注意BNC 女性"中消失的破折号)
(note the disappearing dash in "BNC Female")
我最接近的是使用这个:/(?:[^( )])\-(?:[^( )])/g
The closest I am getting is using this:/(?:[^( )])\-(?:[^( )])/g
但这会导致它找到前面的单个字母、破折号和后面的单个字母:
but that results with it finding the single letter ahead, the dash, and the single letter following:
适配器 - BNC 公头到 BNC-F母头，直角
为什么要选择前/后字符?这不是:
WHY is it selecting the pre/post characters? Is this not:
(?:[^( )]) 查找除空格以外的任何内容(作为非捕获组)...
(?:[^( )]) find anything except a space (as a noncapturing group)...
\- ... 后跟破折号 ...
\- ... that follows with a dash ...
(?:[^( )]) ... 后跟除空格外的任何内容(作为非捕获组)
(?:[^( )]) ... and is followed by anything except a space(as a noncapturing group)
我更接近的是我将第一项替换为 (?=[^( )]) 但如果我将第三项更改为 (?![^( )]) 我回到了我开始的地方 - 只需选择两个空格之间的破折号.GRRRR.
I get even closer is I replace the first term with (?=[^( )]) but if I change the third term to (?![^( )]) I'm back to where I started - just selecting the dash in between the two spaces. GRRRR.
更多示例请访问 http://regexr.com/444i2
推荐答案
要忽略已经带有前/后空间的破折号，您可以使用肯定的 lookarounds 断言左侧和右侧的内容是非空白字符 \S
To ignore dashes already with a pre/post space you could use positive lookarounds to assert that what is on the left and on the right are a non whitespace character \S
在替换中使用空格.
(?<=\S)-(?=\S)
这篇关于正则表达式找到破折号的实例，但不是 <space>dash<space>的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！