UITableViewController中的静态单元格在同一笔尖上打开不同的URL

问题描述

我对UITableViewController很陌生，我想创建一个静态单元格UITableViewController，每个静态单元格都打开相同的nib文件，但UIWebView的URL将不同.例如第1行将打开google.com，而yahoo.com中将打开第2行.我可以知道该怎么做吗?

I am quite new to UITableViewController, I would like to make a static cells UITableViewController and each static cells open up the same nib file but the URL of the UIWebView will be different. e.g. row 1 will open google.com and row 2 in yahoo.com. May I know how can i do that?

谢谢

推荐答案

您将要实现tableview委托方法 tableView:didSelectRowAtIndexPath:，这将允许您询问tableview哪个单元格被选中，然后采取适当的措施.一个例子是:

You'll want to implement the tableview delegate method, tableView:didSelectRowAtIndexPath:, this will allow you to ask the tableview which cell was selected and then take the appropriate action. An example would be:

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath];
    if ([cell.textLabel.text isEqualToString:@"google"]) {
        // open google
    } else if ([cell.textLabel.text isEqualToString:@"yahoo"]) {
        // open yahoo
    }
}

编辑以回答评论中的问题

您没有说明，但是从阅读您的问题开始，我猜您正在使用单独的nib文件，并希望在用户选择一个静态单元格时在屏幕上推送另一个控制Web视图的视图控制器.为此，请执行以下步骤:

You didn't state this, but from reading your question, I'm guessing you are using separate nib files and want to push another view controller on screen that controls a web view when the user selects one of the static cells. The steps to do this are to:

1. 创建新的VC
2. 将要加载的URL赋予公共属性
3. 将VC推送到屏幕上

代码类似于:

 WebViewController webVC = [[WebViewController alloc] initWithNibName:@"your nib name" bundle:[NSBundle mainBundle]];
 webVC.url = // some NSURL object, or maybe just a string that has the URL - that's up to you
 [self.navigationController pushViewController:webVC animated:YES]

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