任何人都有更好的解决方案为了获得从A到BI的最短路线，建议使用alternatives = true来进行不同的查询。
参数，避免=收费，避免=高速公路之间的避免参数玩，然后我会比较所有结果以选择最短的路线。
directionsService = new google.maps.DirectionsService;
//避免收费
directionsService.route（{
origin：{
'placeId'：originId
}，
destination：{
'placeId'：destinationId
}，
provideRouteAlternatives：true，
avoidTolls：true，
travelMode：google.maps.TravelMode.DRIVING
}，function（response，状态）{
if（status === google.maps.DirectionsStatus.OK）{
routesResponses.push（response）;
}
else {
window。警报（由于'+状态导致方向请求失败）;
}
}）;
//避开高速公路
directionsService.route（{
origin：{
'placeId'：originId
}，
destination：{
'placeId'：destinationId
}，
provideRouteAlternatives：true，
avoidHighways：true，
travelMode：google.maps.TravelMode.DRIVING
}，function（response，状态）{
if（status === google.maps.DirectionsStatus.OK）{
routesResponses.push（response）;
}
else {
window。 alert（'Directions请求失败，原因是'+状态）;
}
//结果分析和绘制路线
var faster = Number.MAX_VALUE，
最短= Number.MAX_VALUE;
r outesResponses.forEach（function（res）{
res.routes.forEach（function（rou，index）{
console.log（distance of route+ index +：，rou.legs [0 ] .distance.value）;
console.log（路由持续时间+ index +：，rou.legs [0] .duration.value）;
if（rou.legs [0] .distance.value< shortest）shortest = rou.legs [0] .distance.value;
if（rou.legs [0] .duration.value<最快）最快= rou.legs [0] .duration.value;
））
}）
console.log（shortest：，最短）;
console.log（最快：，最快）;
//以绿色和红色绘制路线
routesResponses.forEach（function（res）{
res.routes.forEach（function（rou，index）{
new google .maps.DirectionsRenderer（{
map：map，
directions：res，
routeIndex：index，
polylineOptions：{
strokeColor：rou.legs [0]。 duration.value ==最快？red：rou.legs [0] .distance.value ==最短？darkgreen：blue，
strokeOpacity：rou.legs [0] .duration.value = =最快？0.8：rou.legs [0] .distance.value ==最短？0.9：0.5，
strokeWeight：rou.legs [0] .duration.value ==最快？9：rou.legs [0 ] .distance.value == shortest？8：3，
}
}）
}）
}）
}）;
}
}
I am making a taxi fare calculator. One of the business requirements is that, the company wants the shortest and fastest route options. I know Google directionService by default searched for the fastest route. I set the "avoidhighways" option in request parameter to true in order to get the shortest route, but I am not quite happy with the result.
Anyone have a better solution than that??
To obtain the shortest route from A to B I would suggest to make different queries with the "alternatives=true" parameter, playing with the "avoid" parameter between avoid=toll, avoid=highways, and then I would compare all results to pick the shortest route.
directionsService = new google.maps.DirectionsService;
//avoiding tolls
directionsService.route({
origin: {
'placeId': originId
},
destination: {
'placeId': destinationId
},
provideRouteAlternatives: true,
avoidTolls: true,
travelMode: google.maps.TravelMode.DRIVING
}, function(response, status) {
if (status === google.maps.DirectionsStatus.OK) {
routesResponses.push(response);
}
else {
window.alert('Directions request failed due to ' + status);
}
});
//avoiding highways
directionsService.route({
origin: {
'placeId': originId
},
destination: {
'placeId': destinationId
},
provideRouteAlternatives: true,
avoidHighways: true,
travelMode: google.maps.TravelMode.DRIVING
}, function(response, status) {
if (status === google.maps.DirectionsStatus.OK) {
routesResponses.push(response);
}
else {
window.alert('Directions request failed due to ' + status);
}
//Results analysis and drawing of routes
var fastest = Number.MAX_VALUE,
shortest = Number.MAX_VALUE;
routesResponses.forEach(function(res) {
res.routes.forEach(function(rou, index) {
console.log("distance of route " +index+": " , rou.legs[0].distance.value);
console.log("duration of route " +index+": " , rou.legs[0].duration.value);
if (rou.legs[0].distance.value < shortest) shortest = rou.legs[0].distance.value ;
if (rou.legs[0].duration.value < fastest) fastest = rou.legs[0].duration.value ;
})
})
console.log("shortest: ", shortest);
console.log("fastest: ", fastest);
//painting the routes in green blue and red
routesResponses.forEach(function(res) {
res.routes.forEach(function(rou, index) {
new google.maps.DirectionsRenderer({
map:map,
directions:res,
routeIndex:index,
polylineOptions:{
strokeColor: rou.legs[0].duration.value == fastest? "red":rou.legs[0].distance.value == shortest?"darkgreen":"blue",
strokeOpacity: rou.legs[0].duration.value == fastest? 0.8:rou.legs[0].distance.value == shortest? 0.9: 0.5,
strokeWeight: rou.legs[0].duration.value == fastest? 9:rou.legs[0].distance.value == shortest? 8: 3,
}
})
})
})
});
}
}
这篇关于一种在Google Maps API v3中查找最短和最快路线的优雅方式？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！