无法使用将play.mvc.WebSocket返回为Play中请求的处理程序的方法吗?

问题描述

GET    /status        controllers.Application.handleWebSocketConnection()

这是相关的源代码.

public WebSocket handleWebSocketConnection() {
    return WebSocket.withActor(new F.Function<ActorRef, Props>() {
        @Override
        public Props apply(ActorRef actorRef) throws Throwable {
            return UserActor.props(actorRef, "");
        }
    });
}

这是我的build.sbt

here is my build.sbt

import play.routes.compiler.InjectedRoutesGenerator
import play.sbt.PlayScala

name := "hello"

version := "1.0"

lazy val `dashboard` = (project in file(".")).enablePlugins(PlayScala)

scalaVersion := "2.11.8"

libraryDependencies ++= Seq(
  jdbc ,
  cache ,
  ws   ,
  specs2 % Test,
  "io.netty" % "netty-all" % "4.0.0"
)

unmanagedResourceDirectories in Test <+=  baseDirectory ( _ /"target/web/public/test" )  

resolvers ++= Seq(
  "scalaz-bintray" at "https://dl.bintray.com/scalaz/releases"
)

routesGenerator := InjectedRoutesGenerator

fork in run := true

我正在使用Play版本2.4.2，并且所有源代码都在Java 8中.出现以下错误.我不确定我的路线和控制器在做什么.我在这里点击了链接.

I am using Play version 2.4.2 and all the source code is in java 8. I get the following error. I am not sure what is going with my routes and the controller. I followed the link here.

[error] /Users/hello/Documents/java/test_app/conf/routes:8: Cannot use a method returning play.mvc.WebSocket[?0] as a Handler for requests

[error] GET    /status       controllers.Application.handleWebSocketConnection()        

[error] /Users/hello/Documents/java/test_app/conf/routes:8: not enough arguments for method createInvoker: (implicit hif: play.core.routing.HandlerInvokerFactory[play.mvc.WebSocket[?0]])play.core.routing.HandlerInvoker[play.mvc.WebSocket[?0]].

[error] two errors found


[error] (compile:compile) Compilation failed

有什么想法吗?

推荐答案

我没有需要添加评论的代表...所以我们开始:

I don't have the rep needed to add a comment... so here we go:

我想知道指定您的websocket处理的消息类型是否可以解决此问题，请尝试:

I'm wondering if specifying the type of messages handled by your websocket would fix the problem, try:

public WebSocket<String> handleWebSocketConnection()

这当然是假设您的websocket期望从浏览器输入字符串以及将字符串发送回.

This is of course assuming your websocket is expecting Strings coming in from the browser as welle as send Strings back.

这篇关于无法使用将play.mvc.WebSocket返回为Play中请求的处理程序的方法吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！