Java(Stack& Heap)-在这个简单的示例中，明智地执行内存操作

问题描述

在此示例中，任何人都可以解释在内存方面(堆栈和堆)会发生什么情况?如果我正确理解，java会将对象存储在堆上，因此i1将在堆上...与字符串相同吗?但是i2呢，考虑到它是一个类字段声明.

Anyone could explain what happens memory wise (Stack & Heap) in this example? If I understand it correctly, java stores objects on the heap, so i1 will be on the heap... same with string? But what about i2, considering it is a class field declaration.

public ExampleClass {
   Integer i1=new Integer(1);
   int i2 = 2;
   String str = "abc";
}

推荐答案

在您拥有诸如new ExampleClass()之类的代码之前，什么都不会发生.完成此操作后，将在堆上分配一个新对象.其中将包括对i1，i2和str的引用.我猜想因为您不在使用方法中，所以i2会在后台自动转换为等效于Integer i2 = new Integer(0)的形式.所有这三个引用都将指向同样也在堆上分配的对象.请注意，字符串是不可变的，因此，如果已有String且值为"abc"，则引用可能指向该字符串.

Nothing happens until you have some code like new ExampleClass(). Once you do that, a new object is allocated on the heap. Included in that will be references to i1, i2, and str. I'm guessing that since you're not in a method, that i2 will be automatically converted behind the scenes to the equivalent of Integer i2 = new Integer(0). All 3 of these references will be pointing to objects also allocated on the heap. Note that strings are immutable so if there is already a String with the value "abc", then the reference may point to that.

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