Quicksort（Java）导致在array.length>处的StackOverFlow; 60K

问题描述

我的代码正常工作（据我所知），直到我的输入数组大小（ a.length ）大约为62,000，此时我一直得到的StackOverflowError 。我以前曾使用2次递归调用 quicksort （小于和大于数据透视 q ）然后我切换尾递归。如您所见，我选择了pivot作为数组末尾的值。我知道这不是选择数据透视表的最佳方法，但我仍然不应该看到 StackOverFlowError s，数组大小这么小，对吧？可能是什么导致了这个？提前致谢！这是我的代码：

My code works properly (to my knowledge) up until my input array size (a.length) is around 62,000 at which time I consistently get a StackOverFlowError. I previously had used 2 recursive calls to quicksort (less than, and greater than the pivot q) and then I switched to tail recursion. As you can see, I'm selecting the pivot to be the value at the end of the array. I know this isn't the best way to choose a pivot, but I still shouldn't be seeing StackOverFlowErrors with an array size this small, right? What could be causing this? Thanks in advance! Here's my code:

    public static void quicksort(int[] a, int p, int r)
    {
        int q;
        while (p < r)
        {
            q = partition(a, p, r);
            quicksort(a, p, q - 1);
            p = q + 1;
        }
    }

    public static int partition(int[] a, int p, int r)
    {
        int j = p - 1;
        int x = a[r];
        for (int i = p; i < r; i++)
        {
            if (a[i] <= x)
            {
                j++;
                swap(a, i, j);
            }
        }
        j++;
        swap(a, j, r);
        return j;
    }

    private static void swap(int[] a, int i, int j)
    {
        int tmp = a[i];
        a[i] = a[j];
        a[j] = tmp;
    }

推荐答案

最坏情况输入（排序顺序）使快速排序Θ（n ^ 2）。 分区总是在分区的一侧放置一个元素（Cormen等人）。通过随机化排序（选择随机数据）没有特定的输入引发其最坏情况行为。

The worst-case input (sorted order) makes quicksort Θ(n^2). Partition always puts a single element on one side of the partition (Cormen et al.). By randomizing the sort (choosing a random pivot) no particular input elicits its worst-case behavior.

import java.util.Random;

public class Quicksort
{
     private static Random rand = new Random();

     public static void quicksort(int[] arr, int left, int right)
     {
          if (left < right)
          {
               int pivot = randomizedPartition(arr, left, right);
               quicksort(arr, left, pivot);
               quicksort(arr, pivot + 1, right);
          }
     }

     private static int randomizedPartition(int[] arr, int left, int right)
     {
          int swapIndex = left + rand.nextInt(right - left) + 1;
          swap(arr, left, swapIndex);
          return partition(arr, left, right);
     }

     private static int partition(int[] arr, int left, int right)
     {
          int pivot = arr[left];
          int i = left - 1;
          int j = right + 1;
          while (true)
          {
               do
                    j--;
               while (arr[j] > pivot);

               do
                    i++;
               while (arr[i] < pivot);

               if (i < j)
                    swap(arr, i, j);
               else
                    return j;
          }
     }

     private static void swap(int[] arr, int i, int j)
     {
          int tmp = arr[i];
          arr[i] = arr[j];
          arr[j] = tmp;
     }

     // Sort 100k elements that are in reversed sorted order
     public static void main(String[] args)
     {
          int arr[] = new int[100000];
          for (int i = 0; i < arr.length; i++)
               arr[i] = arr.length - i;

          System.out.println("First 20 elements");
          System.out.print("Before sort: ");
          for (int i = 0; i < 20; i++)
               System.out.print(arr[i] + " ");
          System.out.println();

          quicksort(arr, 0, arr.length - 1);
          System.out.print("After sort: ");
          for (int i = 0; i < 20; i++)
               System.out.print(arr[i] + " ");
          System.out.println();
     }

}

这篇关于Quicksort（Java）导致在array.length>处的StackOverFlow; 60K的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！