电话号码上有ParseInt NumberFormatException

问题描述

尝试解析电话号码时出现以下错误，5554567899

I'm getting the following error when trying to parse the phone number, "5554567899"

java.lang.NumberFormatException: For input string: "5554567899"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:495)
at java.lang.Integer.parseInt(Integer.java:527)
...

显然，电话号码可以解析。我甚至引用了，字节码结果是

Obviously, the phone number is able to be parsed. I even referenced this question, and the byte code result was

53,53,53,52,53,54,55,56,57,57,

因此字符串中没有不可见的字符。我很难过，有人可以帮忙吗？

So there's no invisible characters in the string. I'm stumped, can anyone help?

以下是引发错误的代码部分，供参考：

Here's the section of the code that's throwing the error, for reference:

String fullNumber = null;
        for(Phone phone : party.getPhones()) {
            if(phone != null && !phone.getDialNumber().isEmpty()) {
                if(!phone.getAreaCode().isEmpty()) {
                    fullNumber = phone.getAreaCode();
                }
                fullNumber += phone.getDialNumber();
                if(phone1 == null || phone1.equals(0)) {
                    LOGGER.debug(displayCharValues(fullNumber));
                    phone1 = Integer.parseInt(fullNumber);
                }
         }

phone1 是 Java.lang.Integer 类型。

推荐答案

该值超出int范围。将其解析为长变量。

The value exceeds the int range. Parse it into a long variable.

简单测试：

int i = 5554567899;

是编译时错误：int类型的文字5554567899超出范围

is a compile time error: "The literal 5554567899 of type int is out of range"

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