列出理解替换不是float或int的项目

问题描述

我有2个项目清单.

样本输入:

['19(1,B7)', '20(1,B8)']
['16 Hyp', '16 Hyp']
['< 3.2', '38.3302615548213']
['18.6086945477694', '121.561539536844']

我需要查找浮点型或整数型的任何东西并将其删除.所以我需要上面的列表看起来像是:

I need to look for anything that isn's a float or an int and remove it. So what I need the above list to look like is:

['19(1,B7)', '20(1,B8)']
['16 Hyp', '16 Hyp']
['3.2', '38.3302615548213']
['18.6086945477694', '121.561539536844']

我写了一些代码来查找'>'并拆分了第一项，但是我不确定如何让我的'新项'代替旧项:

I wrote some code to find '> ' and split the first item but I am not sure how to have my 'new item' take the place of the old:

这是我当前的代码:

def is_number(s):
    try:
        float(s)
        return True
    except ValueError:
        return False

for i in range(0,len(result_rows)):
    out_row = []
    for j in range(0,len(result_rows[i])-1):
        values = result_rows[i][j].split('+')
            for items in values:
                if '> ' in items:
                newItem=items.split()
                for numberOnly in newItem:
                   if is_number(numberOnly):
                      values.append(numberOnly)

此(打印(值))的输出为

The output of this (print(values)) is

['< 3.2', '38.3302615548213', '3.2']

推荐答案

这看起来更像是一种真正的列表理解方法，可以完成您想要的事情...

This looks more like a true list comprehension way to do what you want...

def isfloat(string):
    try:
        float(string)
        return True
    except:
        return False

[float(item) for s in mylist for item in s.split() if isfloat(item)]
#[10000.0, 5398.38770002321]

或删除float()以将项目作为字符串获取.仅当'>'或'<'时，您才可以使用此列表推导在字符串中找到.

Or remove the float() to get the items as strings. You can use this list comprehension only if '>' or '<' are found in the string.

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