问题描述
Hi，此代码通过给出红色和绿色通道之间以及蓝色和绿色通道之间的畸变中心(x，y)和畸变幅度(alpha)来估计图像中的色差.我在WarpRegion函数中有错误
Hi this code estimates chromatic aberration in an image by giving the center of distortion (x,y) and magnitude of distortion (alpha) between the red and green channels and also between the blue and green channels. I have an error in the WarpRegion function
File "CAfeb.py", line 217, in warpRegion
reg_w = sp.interpolate.interp2d(yrampf,xrampf,Cwarp, yramp1f, xramp1f,'cubic');
File "/usr/lib/python2.7/dist-packages/scipy/interpolate/interpolate.py", line 109, in __init__
'quintic' : 5}[kind]
TypeError: unhashable type: 'numpy.ndarray'
下面是完整的代码-非常感谢您的帮助-谢谢.阿雷伊
Below is the complete code - Any help will be greatly appreciated-Thank you. Areej
import math
from PIL import Image
import numpy as np
from decimal import Decimal
import scipy as sp
from scipy import interpolate
from scitools.std import ndgrid
from scipy import ogrid, sin, mgrid, ndimage, array
def ldimage():
#load image
global im
im = Image.open("/home/areej/Desktop/mandril_color.tif")
def analyzeCA(mode, im):
n_regions = 10;
reg_size = [300, 300];
overlap = 0.5;
levels = 9;
steps = 2;
edge_width = 10;
hist_sz = 128;
# alpha_1 and alpha_2 are assumed to be between these values
w_data = [0.9985, 1.0015];
reg_list=[]
#creating an array of pixels so that we can access them
pix=im.load()
#
#Analyze full image
if mode=='full':
print "Doing a full analysis"
# mx_shift is the third argument in 'full' mode
mx_shift = n_regions;
# [ydim,xdim,zdim]= size(im);
ydim=im.size[0]
xdim=im.size[1]
zdim=3
print "Image dimensions: [ydim, xdim, zdim]= "+str([ydim,xdim,zdim])
global alpha_mx, alpha_mn
alpha_mx = 1 + 4*mx_shift / math.sqrt( xdim*xdim + ydim*ydim );
alpha_mn = 1.0/alpha_mx;
print "alpha_mx= "+str(alpha_mx)
print "alpha_mn= "+str(alpha_mn)
#recompute alpha_1 and alpha_2 to be between
#these new values
w_data = [alpha_mn, alpha_mx];
ew = edge_width;
#take the image minus a ew-wide edge
roi = [ew+1, xdim-ew, ew+1, ydim-ew];
print "edge_width= "+str(ew)
print "roi= "+str(roi)
#Analyze blue to green chromatic aberration
bg_params = parameterSearch( im, [3, 2], roi, ew, hist_sz, w_data);
# Analyze red to green chromatic aberration
rg_params = parameterSearch( im, [1, 2], roi, ew, hist_sz, w_data );
elif mode=='reg':
print "we should do a regional analysis here"
else:
print "unsupported call"
#def estimateCARegions( im, [3, 2], reg_list, settings ):
def parameterSearch( im, colour_space, roi, ew, hist_sz, w_data):
#levels is number of iterations
levels = 8;
steps = 2;
#[ydim,xdim,zdim] = size(im);
ydim=im.size[0]
xdim=im.size[1]
zdim= 3
x_data = [1, xdim];
y_data = [1, ydim];
xlim = x_data;
ylim = y_data;
zlim = w_data;
#work out which of height and width is the bigger
dim = max(xdim,ydim)
print "The highest dimension is : "+str(dim)
#check that roi falls within expected boundries
if ((roi[0] <= ew) or (roi[1] > xdim-ew) or (roi[2] <= ew) or (roi[3] > ydim-ew)):
print "ROI is too close to image edges"
return -1 # TODO: terminate here with an error
#Get image regions
source = im.split()
Cfixed = source[2]
Cwarp = source[1]
#[ydim,xdim,zdim] = size(im);
ydimCwarp=Cwarp.size[0]
xdimCwarp=Cwarp.size[1]
print 'xdimCwarp'+str(xdimCwarp)
roi_pad = [roi[0]-ew, roi[1]+ew, roi[2]-ew, roi[3]+ew];
for levels in range(1,8):
#Guess at a center and then compute best warp
#user defined function linear_space used to generate linearly spaced vectors
x_coords = np.linspace(0,511,steps+2)
y_coords = np.linspace(0,511,steps+2)
z_coords = np.linspace(alpha_mn,alpha_mx,steps+2)
step_x=(xlim[1]-xlim[0])/(steps+1)
start_x=xlim[0]+step_x
end_x=xlim[1]-step_x+0.5
step_y=(ylim[1]-ylim[0])/(steps+1)
start_y=ylim[0]+step_y
end_y=ylim[1]-step_y+0.5
step_z=(zlim[1]-zlim[0])/(steps+1)
start_z=zlim[0]+step_z
fudge_z=step_z/2.0
end_z=zlim[1]-step_z+fudge_z
#Do not include end points in search;
centers_x, centers_y, warps= np.mgrid[start_x:end_x:step_x,start_y:end_y:step_y,start_z:end_z:step_z]
centers_x=centers_x.flatten()
centers_y=centers_y.flatten()
warps=warps.flatten()
mi = np.zeros(centers_x.size)
for k in range(0,centers_x.size):
cx = centers_x[k]
cy = centers_y[k]
wz = warps[k]
#Warp the region
temp_im = warpRegion(Cwarp, roi_pad, [cx, cy, wz])
#correlation
mi[k] = np.corrcoef(Cfixed, temp_im)
#Now pick the best quadrant
v, max_ix = math.max(mi)
ix, jx, kx = arrayInd(mi.size, max_ix);
##The coordinates of err are off by 1 from x_coords and y_coords because
##we did not include the end point
xlim = x_coords([jx, jx+2]);
ylim = y_coords([ix, ix+2]);
zlim = z_coords([kx, kx+2]);
cx = math.mean(xlim);
cy = math.mean(ylim);
wz = math.mean(zlim);
print "x= "+str(cx)
print "y= "+str(cy)
print "z= "+str(wz)
def warpRegion(Cwarp, roi_pad, (cx, cy, wz)):
#Unpack region indices
sx, ex, sy, ey = roi_pad
xramp, yramp = np.mgrid[sx:ex+1, sy:ey+1]
xrampc = xramp - cx;
yrampc = yramp - cy;
xramp1 = 1/wz*xrampc;
yramp1 = 1/wz*yrampc;
xrampf = xrampc.flatten()
yrampf = yrampc.flatten()
xramp1f = xramp1.flatten()
yramp1f = yramp1.flatten()
reg_w = sp.interpolate.interp2d(yrampf,xrampf,Cwarp, yramp1f, xramp1f,'cubic');
ldimage()
analyzeCA('full', im)
推荐答案
DSM正确指出，这不是interp2d的正确调用语法，可以在 scipy.interp2d .如果您先阅读调用语法，然后再次读取错误消息(或模块本身，无论您喜欢使用哪种格式)，您就会认识到您正在尝试将数组用作字典的索引，这自然会引发异常.
As DSM states correctly this is not the correct calling syntax for interp2d which can be viewed at scipy.interp2d. If you would read the calling syntax and then your error message again (or the module itself whichever you prefer) you would recognize that you are trying to use an array as index for a dictionary which will naturally throw an exception.
我认为您要尝试的是在新位置xrampf1，yrampf1处对数组xrampf，yrampf给出的网格进行插值. scipy文档还给出了一个完全相同的用法示例，该示例转换为以下代码:
I think what you are trying to do is an interpolation of the grid given by the arrays xrampf, yrampf at the new positions xrampf1, yrampf1. The scipy documentation also gives an exact same usage example which translate as following to your code:
interp_func = sp.interpolate.interp2d(yrampf, xrampf, Cwarp, kind='cubic')
reg_w = interp_func(yramp1f, xramp1f)
我希望那是你的意图.
亲切的问候
这篇关于python中的色差估计的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！