问题描述
我要提供的数据标注的正则表达式为所指定的密码：
I have to provide a data annotation regex for a password that's specified as:
min 8 chars
min 1 upper
min 1 lower
min 1 numeric
min 1 special char which can ONLY be one of the following:$|~=[]'_-+@. (and the password can contain no other special chars besides these)
这是特殊字符，这是给我头痛的排斥。
It's the exclusion of special characters which is giving me the headache.
我已经想出了这一点，但它只是不工作：
I've come up with this but it just does not work:
"^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[\d])**(?(?!.*[^$|~=[\]'_\-+@.])|([^\W\w])).*$**
它解决了一切，我输入为无效。
It resolves everything I enter as invalid.
而这（对于特殊字符）自己做的工作：
Whereas this (for the special chars) on its own does work:
"(?(?!.*[^$|~=[\]'_\-+@.])|([^\W\w])).*$"
和我知道的第一部分工作，所以我缺少什么让他们一起工作？
and I know the first part works, so what am I missing to make them work together?
另外，有实现这一目标的一个更简单的方法？
Alternatively, is there a much simpler way of achieving this?
（.NET环境）
推荐答案
如果你真的想这样做，在一个正则表达式：
If you really want to do that in one regex pattern:
^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[$|~=[\]'_+@.-])[a-zA-Z0-9$|~=[\]'_+@.-]{8,}$
这是应该做的伎俩。我们要求，下壳体，大写字母，数字和符号与向前看符号。请注意，在字符类中，你需要移动 - 到年底或逃避它。否则，它创建你不想一个字符范围。然后我们使用正常的匹配，以确保有只允许的字符，和至少8人
That should do the trick. We require, the lower case, upper case letter, digit and symbol with lookaheads. Note that in the character class, you need to move - to the end or escape it. Otherwise it creates a character range you don't want. Then we use normal matching to ensure that there are only the allowed characters, and at least 8 of them.
不过，它通常是一个更好的方法做多个测试。单独运行这些模式：
However, it's usually a much better approach to do multiple tests. Run these patterns individually:
[a-z] // does the input contain a lower case letter?
[A-Z] // does the input contain an upper case letter?
\d // does the input contain a digit?
[$|~=[\]'_+@.-] // does the input contain one of the required symbols?
[^a-zA-Z0-9$|~=[\]'_+@.-] // are there invalid characters?
，其中前4应该返回真，最后一个应该返回假。此外，您可以检查 input.Length＆GT; = 8 。这使得更可读code，将让你发出相应的错误消息有关的这的条件没有被满足。
where the first 4 should return true and the last one should return false. In addition you can check input.Length >= 8. This makes for much more readable code and will allow you to issue an appropriate error message about which condition is not fulfilled.
事实上，自上次的模式可以确保只有所需的字符，我们可以简化，必须有一个符号条件，以 [^ A-ZA-Z0-9] （在这两种方法）。但我不知道这是否使事情或多或少的可读性。
In fact, since the last pattern ensures that there are only the desired characters, we can simplify the "there has to be one symbol condition" to [^a-zA-Z0-9] (in both approaches). But I'm not sure whether that makes things more or less readable.
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