通过 xslt 模板添加重复的 XML 代码 n 次

问题描述

我想在 XML 文档中重复以下几行 n 次，n 在变量 $n 中设置

I want to repeat the following lines in an XML document n times, n being set in the variable $n

<Cell ss:StyleID="s22">
    <Data ss:Type="String">WSCEAllergens[i]</Data>
</Cell>

而不是像

<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[0]</Data>
</Cell>
<xsl:if test="$n &gt; 1>
  <Cell ss:StyleID="s22">
    <Data ss:Type="String">WSCEAllergens[1]</Data>
  </Cell>
    <xsl:if test="$n &gt; 2>
      <Cell ss:StyleID="s22">
        <Data ss:Type="String">WSCEAllergens[2]</Data>
      </Cell>
    .
    .
    .
    </xsl:if>
  </xsl:if>

我想用一个优雅的模板来解决这个问题，但我不知道如何将 XML 和文本字符串迭代地粘合在一起以获得这样的东西:

I'd like to solve this with an elegant template, but I have no idea how to iteratively glue XML and text strings together to get something like this:

n=3

<Cell ss:StyleID="s22">
    <Data ss:Type="String">WSCEAllergens[0]</Data>
</Cell>
<Cell ss:StyleID="s22">
    <Data ss:Type="String">WSCEAllergens[1]</Data>
</Cell>
<Cell ss:StyleID="s22">
    <Data ss:Type="String">WSCEAllergens[2]</Data>
</Cell>

我已使用此模板将 Daniel 的代码应用于我的 XSLT

---

I have applied Daniel's code to my XSLT with this template

<xsl:template name="repeater">
  <xsl:param name="string"/>
  <xsl:param name="n"/>
  <xsl:param name="count" select="0"/>
    <xsl:value-of select="normalize-space(
        concat(substring-before($string,'['),
        '[',$count,']',
        substring-after($string,']')))" disable-output-escaping="yes"/>
    <xsl:if test="$n - 1 > $count">
      <xsl:call-template name="copyXML">
        <xsl:with-param name="count" select="$count+1"/>
        <xsl:with-param name="string" select="$string"/>
        <xsl:with-param name="n" select="$n"/>
      </xsl:call-template>
    </xsl:if>
</xsl:template>

并通过以下调用

<xsl:call-template name="repeater">
  <xsl:with-param name="n" select="$nAllergens"/>
  <xsl:with-param name="string">
    <![CDATA[
      <Cell ss:StyleID="s22"><Data ss:Type="String">WSCEAllergens[i]</Data></Cell>
    ]]>
  </xsl:with-param>
  </xsl:call-template>

$nAllergens 是 3，我回来了

$nAllergens being 3, I get back

<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[0]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[1]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[2]</Data>
</Cell>

那很好.但是如果我想得到怎么办

That's good.But what if I want to get

<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[0]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[0]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[1]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[1]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[2]</Data>
</Cell>
<Cell ss:StyleID="s22">
  <Data ss:Type="String">WSCEAllergens[2]</Data>
</Cell>

?

我有a) 在我的模板中添加了第二行b) 将 concat-call 更改为concat(substring-before($string,'['),'[',$count,']',substring-after($string,']'),substring-before($string,'['),'[',$count,']',substring-after($string,']'))

I have a) added a second line to my template b) changed the concat-call to concat(substring-before($string,'['), '[',$count,']',substring-after($string,']'), substring-before($string,'['), '[',$count,']',substring-after($string,']'))

两种方式我都只得到WSCE过敏原[0]WSCE过敏原[0]WSCE 过敏原[1]WSCE 过敏原[2]

Both ways I only get WSCEAllergens[0] WSCEAllergens[0] WSCEAllergens[1] WSCEAllergens[2]

推荐答案

嗯，这很简单:

<xsl:template name="repeat">
    <xsl:param name="string"/>
    <xsl:param name="n"/>
    <xsl:param name="i" select="0"/>
    <xsl:if test="2 * $n > $i">
        <xsl:value-of select="substring-before($string,'[i]')" disable-output-escaping="yes"/>
        <xsl:value-of select="concat('[', floor($i div 2), ']')"/>
        <xsl:value-of select="substring-after($string,'[i]')" disable-output-escaping="yes"/>
        <xsl:call-template name="repeat">
            <xsl:with-param name="string" select="$string"/>
            <xsl:with-param name="n" select="$n"/>
            <xsl:with-param name="i" select="$i + 1"/>
        </xsl:call-template>
    </xsl:if>
</xsl:template>

或者，如果您愿意:

<xsl:template name="repeat">
    <xsl:param name="string"/>
    <xsl:param name="n"/>
    <xsl:param name="i" select="0"/>
    <xsl:if test="$n > $i">
        <xsl:variable name="output">
            <xsl:value-of select="substring-before($string,'[i]')"/>
            <xsl:value-of select="concat('[', $i, ']')"/>
            <xsl:value-of select="substring-after($string,'[i]')"/>
        </xsl:variable> 
        <xsl:value-of select="concat($output, $output)" disable-output-escaping="yes"/>
        <xsl:call-template name="repeat">
            <xsl:with-param name="string" select="$string"/>
            <xsl:with-param name="n" select="$n"/>
            <xsl:with-param name="i" select="$i + 1"/>
        </xsl:call-template>
    </xsl:if>
</xsl:template>

这篇关于通过 xslt 模板添加重复的 XML 代码 n 次的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！