问题描述
我有一个数字池（例如{3,6,7,11,20}），我需要每个数字在我的集合中出现x次。
I got a pool of numbers (for example {3,6,7,11,20}) and i need each number to appear in my collection x times.
我的解决方案是创建一个类，让它称之为元素，两个整数（num，numOfAppearnces）。
My solution was to create a class, let's call it "element", of two integers (num,numOfAppearnces).
我创建了一个元素池然后在arrayList中生成一个0到list.size之间的随机数，并得到存储在随机索引中的数字。
当numOfAppearances减少到0时，我从列表中删除了这个元素。
I created a pool of "elements" in arrayList, and then generated a random numbers between 0 to list.size, and got the number stored in the random index.when numOfAppearances decreased to 0, i deleted this element from the list.
我的问题是，是否有任何其他优雅的解决方案来生成随机数，而不是来自一个范围？
my question is, is there any other elegant solution to generate random number, not from a range?
推荐答案
是的，有更短的方式来实现你所描述的。
Yes, there are shorter ways to achieve what you describe.
例如：
Integer[] arr = {3,6,7,11,20};
List<Integer> shuffled = new ArrayList<>();
for (Integer i : arr)
shuffled.addAll (Collections.nCopies(x,i)); // add i to your List x times
Collections.shuffle(shuffled); // shuffle the List to get random order
或者（如果您不想使用 Collections.nCopies（x，i））：
Or (if you don't want to use Collections.nCopies(x,i)) :
Integer[] arr = {3,6,7,11,20};
List<Integer> shuffled = new ArrayList<>();
for (int j = 0; j < x; j++)
for (Integer i : arr)
shuffled.add (i);
Collections.shuffle(shuffled); // shuffle the List to get random order
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