如何在python列表中找到最小的最近数字

问题描述

我想知道如何找到列表中与给定数字最接近的最小数字.例如:

I want to know how can I find the smallest closest number in a list to a given number.For example:

number = 20

list_of_numbers = [4, 9, 15, 25]

我尝试过:

min(list_of_numbers, key=lambda x:abs(x-number))

输出是25，而不是15.问题是它总是给我最大的最近"而不是最小的最近".

The output is 25 and not 15. The problem is that it always gives me the "biggest closest" and not the "smallest closest".

推荐答案

您可以使key也包含数字本身，并将其用于打破平局:

You could make the key also contain the number itself and use that for breaking ties:

min(list_of_numbers, key=lambda x: (abs(x - number), x))

但是，您的行为很奇怪.这可能是一个错误.您可以使用稳定的sorted来解决此问题:

Your behavior is strange, though. It might be a bug. You might be able to work around it by using sorted, which is stable:

sorted(list_of_numbers, key=lambda x: abs(x - number))[0]

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