问题描述
我一直在寻找在最近的一篇博客杰夫·阿特伍德在。我试图将代码转换在后，以C＃，但我遇到了一个问题。目前在.NET中没有的功能，我知道这将返回z值，给定区域的标准正态曲线下的百分比。推荐值使用的算法有95％和97.5％。其中，你可以看一下在任何统计本书的Z值表。
I been looking at the recent blog post by Jeff Atwood on Alternate Sorting Orders. I tried to convert the code in the post to C# but I ran into an issue. There is no function in .NET that I know of that will return the z-value, given the percentage of area under the standard normal curve. The recommended values to use for the algorithm are 95% and 97.5% which you can look up on the z-value table in any statistics book.
有谁知道如何实施用于z的所有的值或平均值至少6个标准偏差这样的功能。一种方法是将硬编码的值成一个字典，并使用一个查找但必须有计算的确切值的一种方式。
我在解决这一尝试是取标准正态曲线函数的定积分。
Does anyone know how to implement such a function for all values of z or at least to 6 standard deviations from the mean. One way would be to hard code the values into a dictionary and use a look up but there has to be a way of calculating the exact value.My attempt at solving this was to take a definite integral of the standard normal curve function.
Y =（1 /（SQRT（2 * PI）） ）* E ^（ - （1/2）* X ^ 2）
y = (1 / (sqrt(2 * PI))) * e^(-(1/2) * x^2)
这给了我两个X值之间的曲线下面积但后来我坚持...也许我基地的方式，这是不是你会怎么做呢？
This gives me the area under the curve between two x values but then I am stuck… Maybe I am way of base and this is not how you would do it?
感谢。
推荐答案
下面是用Python编写的正态分布一些，但它可以很容易地被翻译C＃中加入一些标点符号。它的代码只是约15行。
Here's some code for the normal distribution written in Python, but it could easily be translated to C# by adding some punctuation. It's just about 15 lines of code.
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