Java Apache HTTPClient不对POST实体进行编码

问题描述

我有一个端点，要求使用格式如下的"authenticity_token":

I have an endpoint that requires an 'authenticity_token' that is in the format like:

Iq2rNXN+OxERv+s6TSloJfKkPZVvqnWe1m0NfODB5OI=

但是，有时它具有特殊"字符，例如:

However, sometimes it has "special" characters, such as:

E7IzeP73OgPGgXM/up295ky1mMQMio2Nb8HMLxJFyfw=

这被编码为:

E7IzeP73OgPGgXM%26%2347%3Bup295ky1mMQMio2Nb8HMLxJFyfw%3D

由于某种原因，端点不喜欢这些特殊字符的编码，并且会认为令牌无效.是否可以添加不编码特定值的POST变量?我目前正在做类似的事情:

For some reason, the endpoint does not like the encoding of those special characters and will think the token is invalid. Is it possible to add a POST variable that does not encode specific values? I am currently doing something like:

    HttpPost post = new HttpPost(URL + NEW_FINDING);
    List <NameValuePair> nvps = new ArrayList <NameValuePair>();
    nvps.add(new BasicNameValuePair("foo", foo));
    nvps.add(new BasicNameValuePair("authenticity_token", authenticityToken));
    post.setEntity(new UrlEncodedFormEntity(nvps));

推荐答案

您始终可以使用ByteArrayEntity或StringEntity代替UrlEncodedFormEntity并自己进行编码.它看起来应该像foo=var1&bar=var2.
您必须设置Content-Type=application/x-www-form-urlencoded
您可能想要找出您的终端期望作为Content-Type标头的application/x-www-form-urlencoded值的字符集参数.然后将其作为参数传递给UrlEncodedFormEntity构造函数.这应该是正确的解决方法.

You can always use ByteArrayEntity or StringEntity instead of UrlEncodedFormEntity and do the encoding yourself. It should look something like foo=var1&bar=var2.
You have to set Content-Type=application/x-www-form-urlencoded
You may want to find out what your endpoint expects as a charset parameter for the application/x-www-form-urlencoded value of the Content-Type header. Then pass it as a parameter to the UrlEncodedFormEntity constructor. This should be the right fix.

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